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Butoxors [25]
1 year ago
10

Can someone tell me what is 9x46288

Mathematics
1 answer:
Bad White [126]1 year ago
4 0
Answer: 416,592

Hope this helps!
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I think I know how to solve this, but could someone please check my work for me?
Fiesta28 [93]
Answer is :

 cos⁻¹[(-1-4√7)/(√17, √8) = 173.33° ≈ 173°

5 0
3 years ago
What is 9 to the of 3
MrRa [10]

Answer:

729

Step-by-step explanation:

8 0
2 years ago
Is each line parallel, perpendicular, or neither parallel nor perpendicular to a line whose slope is −6?
ikadub [295]
Line M with slope 6 is neither, line n with slope -6 is parallel because only lines with same slope are parallel, line p with slope 1/6 is neither. and line q with slope -1/6 is perpendicular because only the reciprocal of a slope is perpendicular, so reciprocal of 6= 1/6 reciprocal of -6=-1/6 reciprocal of 2= 1/2
8 0
3 years ago
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Ax+by=cx+dy <br> Solve for X.<br> Please give step by step instructions!
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X= y(d-b) over a-c would be the answer
6 0
3 years ago
Help me i need to submit to my teacher by 8pm​
Vladimir [108]

Please see the figure. We'll first work out half the area of the rounded triangle, half the unshaded part, then double it, then subtract it from the big square.

Half the area is the circular sector PTQ (with center P, arc TQ) minus the right triangle PUT.

A/2 = area(sector PTQ) - area(triangle PUT)

The triangle is half of equilateral triangle PQT, so a 30/60/90 right triangle so we know the sides are in ratio 1:√3:2 so

TU = (7/2)√3

area(PUT) = (1/2) (7/2)(7/2)√3 = (49/8)√3

area(sector PTQ) = (angle TQP / 360°) πr^2

We know angle TQP is 60° because TQP is equilateral.  r=7.

area(sector PTQ) = (60°/360°) π (7²) = 49π/6

Putting it together,

A/2 = area(sector PTQ) - area(triangle PUT)

A = 2(49π/6 -  (49/8)√3)

A = 49(π/3 - √3/4) square cm

I hate ruining a nice exact answer with an approximation, but they seem to be asking.

A ≈ 30.095057615914535

Check:

I'm not sure how to check it.  I'd estimate it's about 25% bigger than equilateral triangle PQT with area (√3/4)7² ≈ 21.2, so around 27. 30 seems reasonable.

Now the real area we seek is the big square PQRS minus A, so

area = 7² - 30.095057615914535 = 18.904942384086 sq cm

They want square meters for some reason; we scale by (1/100)²

Answer: 0.00189 square meters

7 0
3 years ago
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