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Butoxors [25]
2 years ago
10

Can someone tell me what is 9x46288

Mathematics
1 answer:
Bad White [126]2 years ago
4 0
Answer: 416,592

Hope this helps!
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Meryl needs to cut down 10.510.510, point, 5 trees for every 555 cabins she builds.
Angelina_Jolie [31]

Answer:

3 cabins takes 6.3 trees

7 cabins takes 14.7 trees

Step-by-step explanation:

divided 10.5 by 5= 2.1 trees per cabin

2.1 x however many cabins your gonna build

6 0
3 years ago
50 POINTS AND WILL MARK BRAINLIEST NEED HELP ASAP
trasher [3.6K]

Answer:

Please see attached image and all steps below for both parts

Step-by-step explanation:

Task 1

The following system of equations includes a linear equation and a quadratic one:

\left \{ {{y=x+2} \atop {y=x^2-8x+2}} \right} \}

it can be solved by using substitution in the second equation of the variable "y" by the linear expression of the first equation:

x+2=x^2-8x+2\\x=x^2-8x\\x^2-9x=0\\x\,(x-9)=0

and this product of two factors will e zero when either factor is zero, that is: when x = 0, or when x = 9 [to make zero the binomial(x - 9)]

There are two solutions: x = 0 and x = 9.

When we graph both expressions in the system, we see that the line intercepts the parabola at the points (0, 2) and (9, 11). See attached image.

Task 2

Part 1:

Let's pick 30 as a number larger than 25. 30 can be written as 40 - 10

So we can use:

(40 -10)^2=40^2-2\,(40)\,(10)+ 10^2=1600-800+100=900

to calculate its square.

Part 2:

let's choose a=9 and b=10 so we use:

9^3+10^3=(9 + 10)\,(9^2-(9)\,(10)+10^2)=(19)\,(81-(90)+100)=19\,(81-180+100)=19\,*\,91=1729

8 0
3 years ago
A coin bank that excepts only nickels and dimes contains $9.15. There are three more than twice as many nickels as there are dim
valentinak56 [21]

45 dimes and 93 nickels were in bank

<em><u>Solution:</u></em>

Let "n" be the number of nickels

Let "d" be the number of dimes

We know that,

value of 1 nickel = $ 0.05

value of 1 dime = $ 0.10

<em><u>Given that There are three more than twice as many nickels as there are dimes</u></em>

Number of nickels = 3 + 2(number of dimes)

n = 3 + 2d ---- eqn 1

<em><u>Also given that coin bank that excepts only nickels and dimes contains $9.15</u></em>

number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15

n \times 0.05 + d \times 0.10 = 9.15

0.05n + 0.10d = 9.15  ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 1 in eqn 2

0.05(3 + 2d) + 0.10d = 9.15

0.15 + 0.1d + 0.10d = 9.15

0.2d = 9

<h3>d = 45</h3>

From eqn 1

n = 3 + 2(45)

n = 3 + 90 = 93

<h3>n = 93</h3>

Thus 45 dimes and 93 nickels were in bank

3 0
3 years ago
*****urgent help ****Write 2447457.627 in standard form to a appropriate degree of accuracy pls i need help
erica [24]

Answer:

2.447457627 x 10^6

Step-by-step explanation:

If this helped can i have Brainliest

5 0
3 years ago
Three of the four vertices of a rectangle are located at (4, 2), (7, 2) and (4, 8). a. What are the coordinates of the missing v
34kurt

Answer:

a) The coordinates of the missing vertex = (7, 8)

b) Area = 18 square units

   Perimeter = 18 units

Step-by-step explanation:

a) We know three of the four vertices:

A: (4, 2)           C ______ D(?)

B: (7, 2)               |             |

C: (4, 8)           A |______| B  

To find the coordinates of the missing vertex we need to calculate the distance in the x-direction from point A to point B:

B_{x} - A_{x} = 7 - 4 = 3                    

Hence, the distance of point D from point C in the x-direction is:

D_{x} = C_{x} + 3 = 4 + 3 = 7

Now, to find the coordinate in "y" we need to calculate the distance in the y-direction between point C and point A:

C_{y} - A_{y} = 8 - 2 = 6  

Then, the distance of point D from point B in the y-direction is:

D_{y} = B_{y} + 6 = 2 + 6 = 8

Therefore, the coordinates of the missing vertex (point D) are:

D = (D_{x}, D_{y}) = (7, 8)    

b) The area of the rectangle is:

a = (B_{x} - A_{x})*(C_{y} - A_{y}) = 3*6 = 18 units^{2}

The perimeter is given by:

p = 2*(3 + 6) = 18 units

I hope it helps you!          

8 0
2 years ago
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