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Brilliant_brown [7]
3 years ago
5

What is the sum of all integers x that satisfy 1 < (pi -1 )x < 10?

Mathematics
2 answers:
nasty-shy [4]3 years ago
4 0

Answer:

Step-by-step explanation:

pi - 1 = 3.14 - 1 = 2.14

x has to be an integer, and the result must be greater than 1.

1 works.

1 < 2.14*1 < 10  2.14 is between 1 and 10.

2 works

1 < (2.14)*2 < 10

1 < 4.28 < 10

3 works

1 < 2.14 * 3 < 10

1 < 6.42 < 10

4 might work

1 < 2.14*4 < 10

1 < 8.56 < 10

and it does work.

5 can't work

1 < 5 * 2.14 < 10

1 < 10.7 < 10 is not true.

Answer: 1,2,3,4

DedPeter [7]3 years ago
3 0

Answer:

10

Step-by-step explanation:

pi is 3.14...

pi - 1 is 2.14...

question becomes 1<2.14x and 2.14x < 10

1/2.14 < x, 0.46... < x

x < 10/2.14, x < 4.67...

combining

0.46< x < 4.67

x can be 1, 2, 3, 4

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vovangra [49]
The material costs 5.37 for 1 yard.

 Multiply the cost of 1 yard by the number of yards bought:

5.37 per yard x 4.75 yards = $25.51 Total cost.

The answer would be D.
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3 years ago
Adam and Tom share a sum of money in the ratio 18:17
Digiron [165]

x = total amount split between Adam and Tom.

since we know the total amount split between both in a 18 : 17 ratio is "x", let's divide "x" by (18 + 17) and distribute accordingly to get the amount of each.

\stackrel{Adam~received}{18\cdot \cfrac{x}{18+17}}\qquad \qquad \stackrel{Tom~received}{17\cdot \cfrac{x}{18+17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that Adam got "5" more}}{ \stackrel{Adam}{18\cdot \cfrac{x}{18+17}}~~ = ~~\stackrel{Tom}{17\cdot \cfrac{x}{18+17}~~ + ~~5} }\qquad \implies \qquad \cfrac{18x}{35}~~ + ~~\cfrac{17x}{35}+5

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{35}}{35\left( \cfrac{18x}{35} \right)~~ = ~~35\left( \cfrac{17x}{35}+5 \right)}\implies 18x~~ = ~~17x+175\implies \boxed{x =175} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{Tom~received}{17\cdot \cfrac{x}{18+17}}\implies \cfrac{17(175)}{35}\implies \blacktriangleright 85 \blacktriangleleft

5 0
2 years ago
Solve this equation: -7x + 12 – 2x = 23 + 13.0
LiRa [457]

Answer:

Step-by-step explanation:

We can combine the -7x and the -2x and the left side to get -9x and the 23 and 13 on the right side to get 36.

This gives us

-9x + 12 = 36

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5 0
2 years ago
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Multiply each polynomial <br><br> (x + 5)(x+4)<br><br> teach me step by step
lara [203]

Answer: x^2 + 9x + 20

Step-by-step explanation:

Foil Method: (a + b) (c + d) = ac + ad + bc + bd

Lets say:

a = x

b = 5

c = x

d = 4

Plugging in the numbers: xx + 4x + 5x + 5*4

Combine like terms:

xx = x^2

4x + 5x = 9x

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You're then left with: x^2 + 9x + 20

6 0
3 years ago
Plssss help quick i need it for sum important
Vanyuwa [196]

(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

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