What are the coefficient(s) in the following expression:

Mathematics

1 answer:

mars1129 [50]1 year ago

8 0

Step-by-step explanation:

based on the expression you wrote here, the correct answer is

1, 2, -5, -1, 3

since none of your answer options show this, you must have made a mistake either with the expression itself or with the answer options.

please choose in your original the one matching my answer above.

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Rationalize the denominator of square root of negative 16 over open parentheses 1 plus i close parentheses plus open parentheses

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\\\\\\
\cfrac{i\cdot \sqrt{4^2}}{7+4i}\implies \cfrac{4i}{7+4i}\impliedby 
\begin{array}{llll}
\textit{now, we'll multiply by the}\\
\textit{conjugate of the denominator}
\end{array}\\\\
-------------------------------\\\\$

$\bf \textit{and recall }\textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
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\textit{also recall that }i^2=-1
\\\\
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$\bf \cfrac{4i}{7+4i}\cdot \cfrac{7-4i}{7-4i}\implies \cfrac{4i(7-4i)}{(7+4i)(7-4i)}\implies \cfrac{28i-16i^2}{7^2-(4i)^2}
\\\\\\
\cfrac{28i-16(-1)}{49-(4^2i^2)}\implies \cfrac{28i+16}{49-[16(-1)]}\implies \cfrac{16+28i}{49+16}\implies \cfrac{16+28i}{65}
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\cfrac{16}{65}+\cfrac{28i}{65}$

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