Answer:
magnitude of decrease = 120 - 54 = 66$
the percentage = (66/100)×100 = 66%
<u>Answer:</u>
The expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour
<u>Solution:</u>
Given that,
Distance covered by an elephant in 36 seconds is equal to 1 mile
Therefore, <em>distance covered by the elephant in 1 second</em> is
mile
Therefore, <em>distance covered by the elephant in 60 seconds</em> (60 seconds = 1 minute) is

Therefore, <em>distance covered by the elephant in 60 minute</em> (60 minute = 1 hour) is

Hence the expression that can be used to determine how fast an elephant runs in miles per hour is 100 miles per hour
Answer:
y = (x/(1-x))√(1-x²)
Step-by-step explanation:
The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:
x = r·cos(θ)
y = r·sin(θ)
x² +y² = r²
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r = sec(θ) -2cos(θ)
r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)
r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²
(x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations
x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor
y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)

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The attached graph shows the equivalence of the polar and rectangular forms.
That would be : 6fg^3 + 5f^2g^2 + f^3g - 7....because there are no like terms
Answer:
0 <=t<=21
Step-by-step explanation:
Projectile is Moving upwards on an interval of (0 to 21), if we plot Velocity vs Time and denote positive y-axis above 0 and negative y-axis below 0(for velocity), then from 0 to 21 t projectile is moving upwards and has positive velocity, when the projectile reaches the top of it's motion and returns back down to ground it's velocity is negative and is plotted below the y =0 (note that is for t > 21).
hence for the interval 0 <=t <=21 the instantaneous velocity is positive (Note, instantaneous velocity is also the derivative of the velocity or the slope ).