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luda_lava [24]
2 years ago
5

Use substitution to solve.2x2 = 5 + y4y = -20 + 8x2Solve the first equation for y and substitute it into the se4y = 16x? - 604y

= 16x2 - 608x2 - 20 = -20 + 8x2.X 2x = 5 + 2x2 - 5

Mathematics
1 answer:
Dimas [21]2 years ago
3 0

Step by step explanation:

Lets solve the first equation for y:

2x^2=5+y2x^2-5=yy=2x^2-5

And replacing that value in the second equation we have:

4y=16x^2-604(2x^2-5)=-20+8x^28x^2-20=-20+8x^2

Answer:

After replacing we have:

8x^2-20=-20+8x^2

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