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3 years ago

Which of the following is equivalent to the expression?

Mathematics

1 answer:

rodikova [14]3 years ago

6 0

Answer:

A) −3(x3+2x−1)

Step-by-step explanation:

Factor 3-3x^3-6x to get −3(x3+2x−1)

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Miguel made a circular flower garden with a diameter of 7 feet.

yawa3891 [41]

Answer: ok what is the qustion?

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Step-by-step explanation:

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2 years ago

What is greater 10 5/9 or 10.57

Romashka [77]

Answer:

10.57 is the greater number beacuse 5 divided by nine is 0.5 repeating

Step-by-step explanation:

then just round it to the nearest hundreth

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7 0

3 years ago

Using appropriate properties , find 7/5 × 5/12 − 3/12 × 7/5 − 1/15

Mazyrski [523]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

$\frac{7}{5} \times \frac{5}{12} - \frac{3}{12} \times \frac{7}{5} - \frac{1}{15} = \frac{7}{5} ( \frac{5}{12} - \frac{3}{12} ) - \frac{1}{15} = \frac{7}{5} \times \frac{1}{6} - \frac{1}{15} = \frac{7}{30} - \frac{2}{30} = \frac{5}{30} = \frac{1}{6}$

8 0

2 years ago

A polar bear swims 390 meters at a in 150 seconds, what is the speed of the polar bear?

topjm [15]

The answer is 2.6 m/s

The speed (v) is distance (d) through time (t).
v = d/t

We know:
d = 390 m
t = 150 s

v = d/t
v = 390 m / 150s
v = = 2.6 m/s

4 0

3 years ago

Read 2 more answers

Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29

hram777 [196]

Answer:

$\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }$

Step-by-step explanation:

Hello,

I assume that we are working in $\mathbb{C}$ , otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

$p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0$

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

$p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b$

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

$\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }$

Now, we need to find the zeroes of the second factor, meaning finding x so that:

$x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4} \\ \\ x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\ x = 2+5i \ \text{ or } \ x = 2-5i$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago