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3 years ago

3t - 12 ≤ - 9 pls see attachment

Mathematics

1 answer:

Elena-2011 [213]3 years ago

8 0

Answer:

D : t ≤ 1

Step-by-step explanation:

3t - 12 ≤ - 9

3t - 12 + 12 ≤ - 9 + 12

3t ≤ 3

3t/3 ≤ 3/3

t ≤ 1

For (≤ or <) Arrow points to the negative side

if the symbol is (≥ or ≤) then you fill in the dot

if the symbol is (> or <) then you do not fill in the dot

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What is the value of the entry represented by c41

Elenna [48]

<u>ANSWER</u>

$C_{41}=2$

<u>EXPLANATION</u>

This very simple to do.

First locate the entry in $A_{41}$ in matrix A. That is the entry in the intersection of the fourth row and first column of matrix A. This entry is $7$ .

Then multiply by the scalar which is 2 to get,

$2\times 7=14$ .

Next we locate the entry in $B_{41}$ in matrix B also. Which is $4$ . We multiply by the scalar of $-3$ to get,

$-3\times 4=-12$ .

We now add these two corresponding entries to obtain,

$14+-12=14-12=2$

See diagram

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3 years ago

Find all solutions <br> 36x²+12x=0

FromTheMoon [43]

Answer:

x = -1/3 or 0

Step-by-step explanation:

Given equation:

$36x^{2} + 12x = 0$

We can factor 12x on the L.H.S since 12x is divisible by 36x² and 12x.

$\implies 36x^{2} + 12x = 0$

$\implies 12x(3x + 1) = 0$

This can lead to two solutions. I have listed them below!

<h2>Solution 1:</h2>

Divide 12x on both sides to open the parentheses.

$\implies 12x(3x + 1) = 0$

$\implies \dfrac{12x(3x + 1)}{12} = \dfrac{0}{12}$

<em>Note: zero divided by any non-zero number is 0.</em>

$\implies \dfrac{12x(3x + 1)}{12} = \dfrac{0}{12}$

$\implies 3x + 1 = 0$

Isolate 3x on one side of the equation.

$\implies 3x + 1 = 0$

$\implies 3x = 0 - 1$

$\implies 3x = -1$

Divide 3 both sides to determine the value of x.

$\implies 3x = -1$

$\implies \dfrac{3x}{3} = \dfrac{-1}{3}$

$\implies \boxed{x = \dfrac{-1}{3}}$

<h2>Solution 2:</h2>

Divide (3x + 1) on both sides to isolate 12x.

$\implies 12x(3x + 1) = 0$

$\implies \dfrac{12x(3x + 1)}{(3x + 1)} = \dfrac{0}{(3x + 1)}$

<em>Note: zero divided by any non-zero number is 0.</em>

$\implies \dfrac{12x(3x + 1)}{(3x + 1)} = \dfrac{0}{(3x + 1)}$

$\implies 12x = 0$

Divide 12 both sides to determine the value of x.

$\implies 12x = 0$

$\implies \dfrac{12x}{12} = \dfrac{0}{12}$

$\implies \boxed{x = 0}$

Therefore, the solutions for x are -1/3 or 0.

Learn more about this topic: brainly.com/question/295675

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2 years ago

Read 2 more answers

A box contains

Kobotan [32]

Box 1 : 3 pencils + 7 pens = total of 10
probability of picking a pen is 7/10

box 2 : 3 pencils + 3 crayons = total of 6
probability of picking a crayon is 3/6 which reduces to 1/2

probability of picking both is (7/10 * 1/2) = 7/20 <==

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3 years ago

Jason’s credit card has an apr of 17.02% and a 30-day billling cycle. the following table details jason’s transactions with that

forsale [732]

The method of computing that would result in a greater finance charge is a. the daily balance method will have a finance charge $1.02 greater than the adjusted balance method.

<h3>What is the Adjusted Balance Method?</h3>

This refers to the method of accounting that makes use of the owed amount of money at the end of a billing cycle to make its computation on an account after the credits are calculated.

Hence, we can see that when comparing the adjusted balance method to the daily balance method that calculates the interest charges at the end of the day, the daily balance method would have a higher finance charge.

Read more about adjusted balance methods here:

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2 years ago

Triangle MNP is graphed on a coordinate grid with vertices at M (−3, −6), N (0, 3) and P (6, −3). Triangle MNP is dilated by a s

bulgar [2K]

<h3>Answer: Choice D) (6u, -3u)</h3>

===================================

Explanation:

The letter u represents the scale factor. It is some unknown number.

To form the dilation, we multiply this number u by each coordinate of point P (6, -3)

The x coordinate of P is x = 6. It turns into x*u = 6*u which is the x coordinate of P '

Similarly, y = -3 for point P so y*u = -3*u is the y coordinate of point P '

Therefore, we go from P(6, -3) to P ' (6u, -3u)

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4 years ago