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VashaNatasha [74]
1 year ago
8

Find the coefficient of the x^2 term in the expansion of (5x-2)^6 //Series and sequences precalculus

Mathematics
1 answer:
Serhud [2]1 year ago
7 0

We need to expand the term:

(5x-2)^6

This seems like a colossal task, we would need to multiply (5x-2) 6 times. However, we can use a useful tool that is called the 'Pascal's triangle'

I'll paste an image of it above

We will use it in this way:

Each one of the rows, represent the n in the term:

(x+y)^n

So, if we have the expression (x+y) we will pay attention to the upper row, if we have (x+y)^2 we will need the second row, and so on.

In our case, we need the 6th row.

Now, usually a term of the form

(x+y)^6=ax^6+bx^5y+cx^4y^2+dx^3y^3+ex^2y^4+fxy^5+gy^6

As we say, look at the 6th row of the triangle, the numbers a, b, c,..., and g are given there!

\begin{gathered} a=1 \\ b=5 \\ c=10 \\ d=10 \\ e=5 \\ f=1 \end{gathered}

And we need the term that corresponds to x^2, we need the number e=5!

So, after the expansion, the coefficient of the term x^2 will be equal to 5

You might be interested in
The volume of a sphere is 36 cubic inches. What is the radius of the sphere?
Serjik [45]

Answer:

2.05 inches

Step-by-step explanation:

V = 4/3 x πr³

36=4πr³/3

36x3= 4πr³

108= 4πr³

108/4 = πr³

27= πr^3

27/π =r³

r=

\sqrt[3]{27 \div \pi}

r= 2.048in

round off to 2.05in

<u>PROOF</u>

V = 4÷3 x πr³

V= 4/3 x π(2.05)³

V=4/3 x π8.6

V=4×π×8.6/3

V=108/3

V=36in³

Therefore: radius= <u>2.05 inches</u>

8 0
2 years ago
Consider the following expression and determine which statements are true.
Serhud [2]

Given:

$\frac{7}{r}+2^{3}+\frac{s}{3}+11

To find:

Which statement are true?

Solution:

Option A: The entire expression is a sum.

It is true because it performed addition operation.

Option B: The coefficient of s is 3.

$\frac{7}{r}+2^{3}+\frac{s}{3}+11=\frac{7}{r}+2^{3}+\frac{1}{3}s+11

It is not true because the coefficient of s is \frac{1}{3}.

Option C: The term \frac{7}{r} is a quotient.

If we divide 7 by r, we obtain a quotient.

So it is true.

Option D: The term 2^3 has a variable.

It is not true because it does not contain any variable.

Therefore the entire expression is a sum and the term \frac{7}{r} is a quotient are true statement.

3 0
2 years ago
Bags of pretzels are sampled to ensure proper weight. The overall average for the samples is 9 ounces. Each sample contains 25 b
77julia77 [94]

Answer:

The value is UCL  =  10.8  

Step-by-step explanation:

From the question we are told that

    The sample mean is  \= x  =  9 \  ounce

    The sample size is  n =  25

    The standard deviation is  \sigma =  3 \ ounce

Given that the sample size is not large enough i.e  n<  30  we will make use of the student t distribution table  

From the question we are told the confidence level is  99.7% , hence the level of significance is    

      \alpha = (100 -99.7 ) \%

=>   \alpha = 0.003

Generally the degree of freedom is  df =  n- 1

=>  df =  25 - 1

=>  df =  24  

Generally from the student t distribution table the critical value  of  \frac{\alpha }{2} at a degree of freedom of df =  24   is  

   t_{\frac{\alpha }{2} , 24 } = 3.0

Generally the margin of error is mathematically represented as  

      E = t_{\frac{\alpha }{2} , 24} *  \frac{\sigma }{\sqrt{n} }

=>     E = 3.0 *  \frac{3 }{\sqrt{25} }

=>     E =1.8

Gnerally the  upper control chart limit  for 99.7% confidence is mathematically represented as

         UCL  =  \= x  + E

=>      UCL  =  9 + 1.8  

=>      UCL  =  10.8  

     

4 0
2 years ago
Tiffany was at bat
ozzi

Answer:

6:18 hope this helps good luckkk

5 0
3 years ago
Lines s and t are parallel and r is a transversal.
pshichka [43]

Answer:

The angles that are congruent to 4 are: 3, 8, and 7.

3 and 4 are vertical angles, 8 and 3 are opposite interior angles, 8 and 7 are vertical angles.

Hope this helps!

4 0
2 years ago
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