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diamong [38]
3 years ago
13

Help!

Mathematics
1 answer:
nignag [31]3 years ago
5 0

1) 8 + 4 = -5 + 7

     12   =    2

        FALSE

2) y = -11x + 4

(0, -7):   -7 = -11(0) + 4   ⇒   -7 = 0 + 4   ⇒   -7 = 4   False

(-1, -7):  -7 = -11(-1) + 4   ⇒   -7 = 11 + 4   ⇒   -7 = 15   False

(1, -7):  -7 = -11(1) + 4   ⇒   -7 = -11 + 4   ⇒   -7 = -7   True

(2, 26): 26 = -11(2) + 4   ⇒   26 = -22 + 4   ⇒   26 = -18   False

Answer: C

3) Input       Output

     0                0

  <u>   1    </u>             3            

    2             <u>    6  </u>

    3                 9

 <u>   4    </u>          <u>  12   </u>

    5                 15

    6              <u>   18  </u>

Rule: input is being added by 1, output is 3 times x

4) c = 65h

5) 2x = -6

   \frac{2x}{2} = \frac{-6}{2}

    x = -3

6) 8j - 5 + j = 67

        9j - 5 = 67   <em>added like terms (8j + j)</em>

       <u>      +5</u>   <u>+5 </u>

        9j      = 72

       \frac{9j}{9} = \frac{72}{9}

        j      = 8

7) y = mx + b

<u>   -b</u>    <u>      -b  </u>

y - b = mx

\frac{y - b}{x} = \frac{mx}{x}

\frac{y - b}{x} = m

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Solve each equation
Sidana [21]
A)25.5

B)b=-4

C)c=18

D)d=-8

Hope this helps if appreciate brainiest
7 0
3 years ago
(2a^2b + 3ab^2 - b^3) - (4b^3 - 3ab^2 -6a^2b)
skelet666 [1.2K]

<em>Hi there!</em>

<em>~</em>

<em></em>(2a^2b+3ab^2-b^3)-(4b^3-3ab^2-6a^2b)<em></em>

<em>Distribute the Negative Sign:</em>

<em></em>= 2a^2 b + 3ab^2 - b^3 + -1(4b^3 - 3ab^2 - 6a^2b)\\= 2a^2 b + 3ab^2 + - b^3 + -1 (4b^3) + -1 (-3ab^2) + -1 (-6a^2b)\\= 2a^2 b + 3ab^2 + -b^3 + -4b^3 + 3ab^2 + 6a^2 b<em></em>

<em>Combine Like Terms:</em>

<em></em>= 2a^2 b + 3ab^2 - b^3 + -4ab^3 + 3ab^2 + 6a^2 b\\= (2a^2 b + 6a^2 b) + ( 3ab^2 + 3ab^2) + (-b^3 + -4b^3) \\= 8a^2 b + 6ab^2 + -5b^3<em></em>

<em>Answer : </em>8a^2 b + 6ab^2 + -5b^3<em></em>

<em>Hope this helped you!</em>

7 0
3 years ago
Lori is three times as old as Michelle. In five years Michelle's age will be one half of Lori's age. How old are Lori and Michel
AURORKA [14]

Answer:

Lori's age is 15 years old and Michelle's age is 5 years old now

Step-by-step explanation:

Let

x-----> Lori's age

y ----> Michelle's age

we know that

x=3y-----> equation A

(y+5)=\frac{1}{2}(x+5) ----> equation B

substitute equation A in equation B and solve for y

(y+5)=\frac{1}{2}(3y+5)

2y+10=(3y+5)

3y-2y=10-5

y=5

Find the value of x

x=3(5)=15

therefore

Lori's age is 15 years old and Michelle's age is 5 years old now

7 0
3 years ago
Fill the blank bellow.....
Lemur [1.5K]

slope = (y2-y1)/(x2-x1)

the first slope is 0 (horizontal line)

second slope is undefined (vertical line)

3 0
2 years ago
Solve F(x) for the given domain. <br> F(x) = x ^2 + 3x - 2 <br> F(3) = <br> 13<br> 16<br> 40
olchik [2.2K]
F(3) = 16, you simply plug in 3 for x to find the answer.
6 0
3 years ago
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