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diamong [38]
4 years ago
13

Help!

Mathematics
1 answer:
nignag [31]4 years ago
5 0

1) 8 + 4 = -5 + 7

     12   =    2

        FALSE

2) y = -11x + 4

(0, -7):   -7 = -11(0) + 4   ⇒   -7 = 0 + 4   ⇒   -7 = 4   False

(-1, -7):  -7 = -11(-1) + 4   ⇒   -7 = 11 + 4   ⇒   -7 = 15   False

(1, -7):  -7 = -11(1) + 4   ⇒   -7 = -11 + 4   ⇒   -7 = -7   True

(2, 26): 26 = -11(2) + 4   ⇒   26 = -22 + 4   ⇒   26 = -18   False

Answer: C

3) Input       Output

     0                0

  <u>   1    </u>             3            

    2             <u>    6  </u>

    3                 9

 <u>   4    </u>          <u>  12   </u>

    5                 15

    6              <u>   18  </u>

Rule: input is being added by 1, output is 3 times x

4) c = 65h

5) 2x = -6

   \frac{2x}{2} = \frac{-6}{2}

    x = -3

6) 8j - 5 + j = 67

        9j - 5 = 67   <em>added like terms (8j + j)</em>

       <u>      +5</u>   <u>+5 </u>

        9j      = 72

       \frac{9j}{9} = \frac{72}{9}

        j      = 8

7) y = mx + b

<u>   -b</u>    <u>      -b  </u>

y - b = mx

\frac{y - b}{x} = \frac{mx}{x}

\frac{y - b}{x} = m

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The statement that is true about the dot plots is:  Range for Week 1 equals range for Week 2.

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Range for Week 1:

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Range for Week 2:

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2 years ago
Please Help Me, This Is So Difficult.
Julli [10]

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<h3>How to define the variables</h3>

Let x = number of non-stop airplanes

Let y = number of two-stop airplanes

<h3>The system of linear inequalities</h3>

Using the variables in (a), we have the following constraints

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Total Airplanes constraint: x + y <= 12

<h3>Graph the feasible region.</h3>

In (b), we have the following system of linear inequalities

150x + 100y <= 1200

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See attachment for the graph

<h3>The objective function</h3>

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From the graph of the function, the optimal solution is:

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So, the maximum revenue is:

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Answer:

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Step-by-step explanation:

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