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1 year ago

Barry's final score is 45 which player had the greater final score?

Mathematics

1 answer:

natali 33 [55]1 year ago

5 0

The player with the greater final score is of:

Barry.

<h3>How to obtain which player had the greater final score?</h3>

Barry's final score is given as follows:

45.

Then we have to obtain Lee's score, from the description given in the missing information section.

Lee's scored is obtained as follows:

Starts at -350.

Answers a 275-point question correctly, hence - 350 + 275 = -75.

Answers a 70 - point question correctly, hence -75 + 70 = -5.

Answers a 50 - point question incorrectly, hence: -5 - 50 = -55.

Thus Lee's final score is given as follows:

-55.

The classifications of the final scores according to the signals are given as follows:

Barry: positive score.

Lee: negative score.

A positive score will always be greater than a negative score, hence Barry had the greater final score.

<h3>Missing information</h3>

Lee and Barry play a trivia game in which questions are worth different numbers of points. If a question is answered correctly, a player earns points. If a question is answered incorrectly, the player loses points. Lee currently has -350 points.

a. Before the game ends, Lee answers a 275 -point question correctly, a 70 -point question correctly, and a 50 -polnt question incorrectly. Write and find the value of an expression to find Lee's final score.

b. Barry's final score is 45. Which player had the greater final score?

More can be learned about addition of measures at brainly.com/question/24342899

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c. 0.00058

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Step-by-step explanation:

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-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

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$P(X$

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c. The proportion of customers consuming more than 5000 calories is calculated as:

$P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058$

Hence, the proportion of customers consuming over 5000 calories is 0.00058

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1% is equivalent to a z value of 0.50399.

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$0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09$

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

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beks73 [17]

The person above me is right. It’s A , you have to add

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