8) The graphical representation of a linear polynomial is

Mathematics

1 answer:

pickupchik [31]3 years ago

5 0

Answer:

Straight line

Step-by-step explanation:

if for a linear polynomial ax + b, a ≠ 0, the graph of y = ax + b is a straight line which intersects the x-axis at exactly one point, namely, (- b/a, 0). Also, this linear polynomial has only one zero which is the x-coordinate of the point where the graph of y = ax + b intersects the x-axis.

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a diagram shows one of the post at the end of Manuel driveway it length is 11.5 the breadth is 11.5 and the width is 7.4 what is

lisov135 [29]

Because vol= length x width x height , and assuming that the height is 11.5 because breadth means width but you already have a width then, vol= 11.5 x 7.4 x 11.5, vol = 978.65

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3 years ago

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How can you find the constant of

solong [7]

Answer:

To find the constant of proportionality from the coordinates of

one point on the graph are as follows :-

1.) Find two easy points.

2.) Start with the leftmost point and count how many squares you need to up to get to your second point.

3.) Count how many squares you need to go to the right.

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Two boats leave the same place at the same time. The first boat heads due north at 10 kilometers per hour. The second boat heads

Maksim231197 [3]

Answer:

18.87 km/hr

Step-by-step explanation:

First boat is heading North with a speed of 10 km/hr.

Second boat is heading West with a speed of 16 km/hr.

Time for which they move = 2.5 hours

To find:

The speed at which the distance is increasing between the two boats.

Solution:

Let the situation be represented by the attached diagram.

Their initial position is represented by point O from where they move towards point A and point B respectively.

$Distance = Speed \times Time$

$Distance\ OA = 10 \times 2.5 = 25\ km$

$Distance\ OB = 16 \times 2.5 = 40\ km$

We can use Pythagorean Theorem to find the distance AB.

AB is the hypotenuse of the right angled $\triangle AOB$ .

According to Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^2 = 25^2 + 40^2\\\Rightarrow AB^2 = 2225^2\\\Rightarrow AB^2 \approx 47.17\ km$