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3 years ago

8) The graphical representation of a linear polynomial is

Mathematics

1 answer:

pickupchik [31]3 years ago

5 0

Answer:

Straight line

Step-by-step explanation:

if for a linear polynomial ax + b, a ≠ 0, the graph of y = ax + b is a straight line which intersects the x-axis at exactly one point, namely, (- b/a, 0). Also, this linear polynomial has only one zero which is the x-coordinate of the point where the graph of y = ax + b intersects the x-axis.

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What is -18+6+3r+13r=

kvasek [131]

If this is just an expression, then all you have to do is combine like terms, or groups of numbers and variables that have the same variable.

When simplified, you get the equation

-12+ 16r or

-18+6+3r+13r=16r-12

7 0

2 years ago

Solve For Each Variable.

bixtya [17]

The first equation given $6=1-2n+5$

We have to add 1 and 5 to the right side first. We will get,

$6= 6 - 2n$

To get rid of 6 from the right side we have to subtract 6 from both sides.

$6-6 = 6-6-2n$

$6-6 = -2n$

$0=-2n$

To find n we have to move -2 to the other side by dividing both side by -2.

$0/-2 = -2n/-2$

$0= n$

$n=0$

So we have got the required answer for the first question.

The solution is n = 0.

The second equation given,

$8x-2 = -9+7x$

First we have to move 7x to the left side by subtracting it from both sides.

$8x-7x-2 = -9+7x-7x$

$8x-7x-2 = -9$

$x-2 = -9$

Now we have to move -2 to the right side by adding 2 to both sides.

$x-2+2 = -9+2$

$x = -9+2$

$x = -7$

We have got the required answer for the second question.

The solution is x = -7.

The third equation given,

$-8 = -(x+4)$

We have to get rid of that negative sign from both sides. As we have negative sign to both sides we can cancel it out. We will get,

$8=x+4$

Now we have to move 4 to left side by subtracting it from both sides.

$8-4 = x+4-4$

$8-4 = x$

$4=x$

$x = 4$

So we have got the required answer .

The solution is x = 4.

3 0

2 years ago

The graph for the equation y=-2x+1 is shown below.

Tpy6a [65]

Answer:

Step-by-step explanation:

Given the equation y=-2x+1 and given another equation y=mx+b in order for us to have no solution we must guarantee that both lines do not intersect. Recall that m is the slope of the second equation and b the y-intercept. To guarantee that both lines don't intersect, they must be parallel. To have this result, we must have that they have the same slope but different y intercept. That is take m = -2 and b any value different to +1. For example, the b = 6. So

y = -2x+6 = -2(x-3) is another equation that gives no solution to the system.

3 0

3 years ago

Solve x^2 – 8x + 41 = 0 for x.

icang [17]

<span> $\displaystyle x^2 - 8x + 41 = 0 \\\\ \Delta=b^2-4ac \\ \Delta=(-8)^2-4\cdot1\cdot41 \\ \Delta=64-164 \\ \Delta=-100 \\ \\ X_{1,2}= \frac{-b\pm i \sqrt{-\Delta} }{2a} = \frac{8 \pm 10i}{2} \\ \\ X1=4-5i \\ \\ X2=4+5i$ </span>

5 0

3 years ago

Two step equation<br><br> n - 5/2 =5

Verdich [7]

Answer:

Step-by-step explanation:

two step equation

n - 5/2 = 5

n = 5 + 5/2

n = 5 + 2.5

n = 7.5

-----------

check

7.5 - 5/2 = 5

7.5 - 2.5 = 5

5 = 5

the answer is good

3 0

1 year ago