Question

(gh)^0 I'm very confused can you show me how to solve this

Answer 1

The expression is:

$(9d^{10})^{-2}$

Simplify the expression:

1. Multiply the exponent outside the parenthesis with every exponent inside the parenthesis,

$\begin{gathered} (9d^{10})^{-2}=9^2d^{(-10)\times2} \\ (9d^{10})^{-2}=9^{-2}d^{-20} \end{gathered}$

Since, exponents in negative form are express as fraction with 1 as numerator.

$\begin{gathered} \mleft(9d^{\mleft\{10\mright\}}\mright)^{\mleft\{-2\mright\}}=9^{-2}d^{\mleft\{-20\mright\}} \\ \mleft(9d^{\mleft\{10\mright\}}\mright)^{\mleft\{-2\mright\}}=\frac{1}{9^2}\times d^{\mleft\{-20\mright\}} \\ \mleft(9d^{\mleft\{10\mright\}}\mright)^{\mleft\{-2\mright\}}=\frac{1}{81}^{}d^{\mleft\{-20\mright\}} \end{gathered}$

Answer: 1/81d^(-20)