Question

a buret is a tool designed to transfer precise amounts of liquid .A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution after how many drips will the volume of the solution in the buret and beaker be equal ?

Answer 1

Let:

Vbu= Volume of the buret

Vbk= Volume of the beaker

A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:

x = Number of drips

a = volume of each drip

$\begin{gathered} Vbu=70-ax \\ Vbk=20+ax \\ \text{where:} \\ a=0.05 \\ Vbu=70-0.05x \\ Vbk=20+0.05x \end{gathered}$

after how many drips will the volume of the solution in the buret and beaker be equal ?​ Vbu = Vbk:

$\begin{gathered} Vbu=Vbk \\ 70-0.05x=20+0.05x \\ \text{Solve for x:} \\ 0.1x=70-20 \\ 0.1x=50 \\ x=\frac{50}{0.1} \\ x=500 \end{gathered}$