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givi [52]
3 years ago
13

Neptune completes 1 1/2 truns about its axis each day.how many truns does it complete in 1 week?​

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0

Answer:Fractions Word Problems – Grade 8

Solve these on a separate sheet of paper.

The following word problems may require you to add, subtract, multiply or

divide fractions.

Read each problem carefully to choose the correct operation. Some of

these are tricky! Be sure to show your work and state your answer in a

sentence!

1. The girl’s hockey team won 6 games, lost 3 games, and tied 2 games. What

fraction of games did they win?

2. In a full set of permanent teeth, ¼ of the teeth are incisors, ¼ are premolars,

and 3/8 are molars. What fraction of all the teeth are incisors, premolars and

molars?

3. Chad made a snack by combining 1/3 of a bowl of granola with ¼ of a bowl of

chopped banana and ½ of a bowl of yoghurt. Did one bowl hold all of the

ingredients at one time? Explain.

4. In the first two hockey games of the year, Rodayo played 1 ½ periods and 1

¾ periods. How many periods in all did he play?

5. Neptune completes 1 ½ turns about its axis each day. How many turns does

it complete in 1 week?

6. Shane has a piece of rope that is 7 4/5 units long. If he cuts it into pieces that

are each 3/5 of a unit long, how many pieces does he have?

7. About

4

3

of the students on the track team are girls. About

4

3

of these girls

are in grade 8. What fraction of the students on the track team are grade 8

girls?

8. Mara spent 3/5 of her vacation in British Columbia. While in that province,

she spent ½ of her time in Vancouver. What fraction of her vacation did

Michaela spend in Vancouver? If her vacation lasted 20 days, how many

days did she spend in Vancouver?

9. Nick mowed about

5

3

of the school lawn yesterday. He mowed another

4

1

of

the lawn this morning. How much is left to mow?

10. Jackie used to be on the phone

2

1

3 times as much as her brother. Her

parents threatened to take away the phone, so she cut down to

5

2

of the time

she used to be on the phone. How many times as much as her brother is

Jackie now on the phone?

Step-by-step explanation:

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Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the
Likurg_2 [28]

Answer:

(a)  moment generating function for X is \frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)

(b) \mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, P(X)=\frac{1}{6}

(a) Moment generating function can be written as M_{x}(t).

M_x(t)=\sum_{x=1}^{6} P(X=x)

M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}

M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)

(b) Now, find E(X) \text { and } E\((X^{2}) using moment generating function

M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)

M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)  

\Rightarrow E(X)=\frac{21}{6}

M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)

M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)

\Rightarrow E\left(X^{2}\right)=\frac{91}{6}  

Hence, (a) moment generating function for X is \frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right).

(b) \mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}

6 0
3 years ago
-8x + 10y + 16x - 2y<br> Simplify and show work
HACTEHA [7]

Answer:

8x+8y

Step-by-step explanation:

7 0
3 years ago
The graph compares the weights in pounds of 100 dogs and cats that are brought in to a veterinarian's office.
GenaCL600 [577]
In case of dogs the value 10 is the minimum value. So all the values lie above 10. In total there were 100 dogs.
So for dogs, we can say number of dogs above the value of 10 pound are 100.

In case of Cats, 10 lies at the position of median. Median is the central value and 50% values lie above the median value. So number of cats with weight above 10 pound is 50.

Thus, we can conclude that there were 50 more dogs than the cats with weight over 10 pounds. So option C gives the correct answer.
8 0
3 years ago
Read 2 more answers
Find the values of the variables in each figure.
Diano4ka-milaya [45]

Answer:

x = 40

Step-by-step explanation:

2x = 4x - 40 (recall properties of a parallelogram)

Solve for x

2x - 4x = 4x - 40 - 4x (subtraction property of equality)

-2x = -40

-2x/-2 = -40/-2 (division property of equality)

x = 20

8 0
3 years ago
3. Calculate the following- show all working out<br>a)7/8 of R60,00​
bagirrra123 [75]

Answer:

5250

Step-by-step explanation:

a. 7/8 of 60,00

a \frac{7}{8} * 60,00

\frac{7*60,00}{8}

\frac{42,000}{8}

5250

7 0
3 years ago
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