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3 years ago

1 A. All master photographers are artists.

Mathematics

1 answer:

Ede4ka [16]3 years ago

7 0

Answer:

A is the appropriate option.

Step-by-step explanation:

The question given is a conditional statement.

With the condition that all master photographers are artist. This implies that any person who is a master photographer is automatically an artist.

A. Comparing the statement here, since Ansel Adam's is a master photographer, he is an artist.

B. Ansel Adams is an artist, but it is possible that not all artists are master photographer.

A is the correct option.

1. All master photographers are artists.

2. Ansel Adams is a master photographer.

Therefore, Ansel Adams is an artist.

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choli [55]

Answer:

Point P = (-9,11)

Step-by-step explanation:

Point M: (1,3) X and Y have the 2 on the bottom right of them

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Hope this helps, good luck! :)

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3 years ago

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Brums [2.3K]

250 + 4 (4x250) = 500

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3 years ago

Which expression is equivalent to 21 × 7?

madreJ [45]

7 x 21 is equivalent to 21 x 7
also 3 x 49

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23 POINTS A 3-column table with 5 rows. Column 1 has entries Mean, median, mode, range, M A D. Column 2 is labeled Noah with ent

jek_recluse [69]

Answer:

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Step-by-step explanation:

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Many people think that a national lobby's successful fight against gun control legislation is reflecting the will of a minority

Andre45 [30]

Answer:

The 95% confidence interval of the true proportion of all Americans who are in favor of gun control legislation is (0.5471, 0.5779).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

A random sample of 4000 citizens yielded 2250 who are in favor of gun control legislation. This means that $n = 4000$ and $\pi = \frac{2250}{4000} = 0.5625$

Estimate the true proportion of all Americans who are in favor of gun control legislation using a 95% confidence interval

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5625 - 1.96\sqrt{\frac{0.5625*0.4375}{4000}} = 0.5471$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5625 + 1.96\sqrt{\frac{0.5625*0.4375}{4000}} = 0.5779$

The 95% confidence interval of the true proportion of all Americans who are in favor of gun control legislation is (0.5471, 0.5779).

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3 years ago