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Dvinal [7]
1 year ago
10

Determine the slope and the y-intercept of the line.

Mathematics
1 answer:
MariettaO [177]1 year ago
4 0

Answer:

Slope = 0, y int = (0,4)

If there is no x variable, slope is 0. y = 4 so no matter what x is (which it will always be 0) the y intercept will always be 4

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Hello answer and I will give you brainliest:No cheating!
stich3 [128]
The answer is 58,875

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2 years ago
Y ≤ -2x + 4. What points satisfy the inequality?
MrRissso [65]
​Subtract 4 from both sides
y−4≤−2x

 Divide both sides by −2
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<span>x  ≤  −   y−4/2<span><span><span><span><span>​​</span></span></span>​​





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3 years ago
What is 456,420 divided by 8.75 million
Travka [436]
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0.05216228571 is the answer.</span>
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3 years ago
A particular isotope has a​ half-life of 74 days. If you start with 1 kilogram of this​ isotope, how much will remain after 150
shtirl [24]

\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}


\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}

6 0
3 years ago
I REALLY NEED HELP FAST PLEASE !!
fiasKO [112]

Answer:

C: √768

Step-by-step explanation:

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

8 0
2 years ago
Read 2 more answers
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