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2 years ago

Please help me out and check the question !! ...

Mathematics

1 answer:

pychu [463]2 years ago

3 0

Answer: 200

Because for each minute it goes up 200 more.

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Solve the equation. x² =96 A 4/6 B 16/6 C 9 D 9,-9

alexgriva [62]

Answer:

x = ± 4 $\sqrt{6}$

Step-by-step explanation:

Given

x² = 96 ( take the square root of both sides )

x = ± $\sqrt{96}$ = ± $\sqrt{16(6)}$ = $\sqrt{16}$ × $\sqrt{6}$ = ± 4 $\sqrt{6}$

3 0

3 years ago

1.325 to the nearest hundreths

12345 [234]

Its 1.33 because you round up if its 5 or greater

4 0

2 years ago

Read 2 more answers

Identify the figure that portrays the translation of the given preimage as indicated by the direction arrow.

ladessa [460]

The parallelogram will translate along the arrow and reach the head of the arrow.

The translation is a category of motion in which one body moves along towards a particular direction and reaches a particular point.

In translation, the rotational motion is not present. Also, the translational motion is a one-dimensional motion.

In the given figure, the parallelogram is present at the tail of the arrow.

The arrow depicts the direction of the translational motion.

So, the parallelogram will reach the end of the arrow as shown in the picture present in the attachment.

For more explanation about translation or rotation, refer to the following link:

hhttps://brainly.com/question/9032434

#SPJ10

6 0

1 year ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

3 years ago

Jacob bought a TV for $178.10, including tax. He made a down payment of $35.00 and paid the balance in 5 equal monthly payments.

sergij07 [2.7K]

178-35=143

143/5= 28.6

he paid $28.6 every month

4 0

2 years ago