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1 year ago

Find the distance between the pair of parallel lines with the given equations.

Mathematics

1 answer:

ZanzabumX [31]1 year ago

8 0

The distance between the two parallel lines is 26 units

<h3>What is are parallel lines?</h3>

Parallel lines are lines that do not meet or intersect.

If y = mx +c as the equation of a straight line

For the line y = -5x

comparing with the standard equation of a line,

y = -5x has no y-intercept, so the coordinates of the point is (0,0)

For the second line y = -5x + 26

comparing with the standard equation

The y-intercept is 26, which means the coordinates of the point is (0, 26)

The distance between these two points is the distance between the two lines.

Formula for distance between two point,

D = $\sqrt{(y_{2} -y_{1}) ^{2} + (x_{2} - x_{1}) ^{2} }$

D = $\sqrt{(26-0)^{2} + (0-0)^{2} }$

D = 26 units

In conclusion, the distance between the two parallel lines is 26 units

Learn more about parallel lines: brainly.com/question/24607467

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5301

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3 years ago

True false a line parallel to one side of a triangle and intersects the other two sides divides the other two sides proportional

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Fatima wants to find the value of sine theta, given cotangent theta = four-sevenths. which identity would be best for fatima to

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By using trigonometric relations, we will find that:

sin(θ) = (√33)/7 = √(33/49)

<h3>How to find the value of the sine?</h3>

Remember that for a right triangle, we have the relations:

cos(a) = (adjacent cathetus)/(hypotenuse)

sin(a) = (opposite cathetus)/(hypotenuse).

Here we know that:

cos(θ) = 4/7

Then we can say that we have a triangle with an adjacent cathetus of 4 units and a hypotenuse of 7 units. Now we need to find the other cathetus.

opposite cathetus = √(7^2 - 4^2) = √33

Then we can write:

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2 years ago

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Convert everything to pints and add them up.
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3 years ago

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sladkih [1.3K]

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2 years ago