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3 years ago

-h+4=-h+4 solve for h

Mathematics

1 answer:

zlopas [31]3 years ago

3 0

Answer:

h=all real numbers

Step-by-step explanation:

both sides are the same, so any number would work

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If x = 0, then

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Ans: 0. fraction is equal to 0 then 0×1000=0

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2 years ago

8. The measure of ZH is (11x - 29). If x= 19,

frez [133]

Answer:

given ,

$\bold{ZH = (11x - 29)}$

Also ,

$\bold{x = 19}$

substituting the value of x in the value of ZH , we get

$\bold{ZH = 11(19) - 29 }\\\bold{ ZH = 209 - 29 }\\ \bold\blue{ZH = 180}$

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2 years ago

Kirans aunt is 17 years older than kiran.

Ostrovityanka [42]

Answer:

Kiran's Aunt will be 32

Step-by-step explanation:

When Kiran was born her/his Aunt would be 17 as the problem says, so just add 15 to 17 to make 32; therefore Kiran's Aunt is 32 years old when Kiran is 15 years old. :)

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2 years ago

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Erms is selling tickets to a musical performance.

Lapatulllka [165]

Answer:

the price of an adult ticket is $3 and a child ticket is $2

Step-by-step explanation:

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2 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm8,0)(±8,0)left parenthesis, plus minus, 8, comma,

mario62 [17]

Answer:

The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

Step-by-step explanation:

The standard form of the equation of an ellipse with center (0 , 0) is

$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ , where

The coordinates of the vertices are (± a , 0)

The coordinates of the foci are (± c , 0) , where c ² = a² - b²

∵ The ellipse is centered at the origin

∴ The center of it is (0 , 0)

∵ It has foci at (± 8 , 0)

- The coordinates of the foci are (± c , 0)

∴ c = ±8

∵ It has Vertices at (± 17 , 0)

- The coordinates of the vertices are (± a , 0)

∴ a = ±17

∵ c² = a² - b²

- Substitute the values of c and a to find b

∴ (8)² = (17)² - b²

∴ 64 = 289 - b²

- Add b² to both sides

∴ b² + 64 = 289

- Subtract 64 from both sides

∴ b² = 225

- Take √ for both sides

∴ b = ± 15

∵ The equation of the ellipse is $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$

- Substitute the values of a and b in it

∴ $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$ ⇒ $\frac{x^{2}}{289}+\frac{y^{2}}{225}=1$

∴ The equation of the ellipse is $\frac{x^{2}}{(17)^{2}}+\frac{y^{2}}{(15)^{2}}=1$

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3 years ago