Equation of the line which passes through the point (-4,5) and the slope of the line is 0 is equal to y = 0x + 5.
As given in the question,
Line passes through the point ( -4 , 5) and the slope of the line is equal to 0.
Standard equation of the line passes through the point ( x₁ , y₁) and slope m is given by :
( y -y₁ ) / ( x - x₁ ) = m
Substitute the given value of the point ( x₁ , y₁) = ( -4, 5 ) and slope m = 0 in the standard form we get,
( y - 5 ) / ( x - (-4)) =0
⇒ ( y - 5 ) = 0( x +4)
⇒ y = 0x + 5
Therefore, equation of the line which passes through the point (-4,5) and the slope of the line is 0 is equal to y = 0x + 5.
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