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babunello [35]
3 years ago
6

What is the product of a+3 and -2a2+15a+6b2

Mathematics
2 answers:
vitfil [10]3 years ago
6 0

Answer:

-2a³+ 9a²  + 45a +6ab² +  18b².

Step-by-step explanation:

Given : a+3 and -2a²+15a+6b².

To find : what is the product.

Solution : We have given

(a+3)( -2a²+15a+6b²).

Distributes a over (-2a²+15a+6b²) and 3 over (-2a²+15a+6b²).

a (-2a²+15a+6b²) + 3 ( -2a²+15a+6b²).

-2a³+15a²+6ab² - 6a²+ 45a + 18b².

Combine like terms

-2a³-  6a² + 15a² + 45a +6ab² +  18b².

-2a³+ 9a²  + 45a +6ab² +  18b².

Therefore, -2a³+ 9a²  + 45a +6ab² +  18b².

DaniilM [7]3 years ago
3 0

Answer:

The third option

Step-by-step explanation:

Given

(a + 3)(- 2a² + 15a + 6b²)

Each term in the second factor is multiplied by each term in the first factor, that is

a(- 2a² + 15a + 6b²) + 3(- 2a² + 15a + 6b²) ← distribute both parenthesis

= - 2a³ + 15a² + 6ab² - 6a² + 45a + 18b² ← collect like terms

= - 2a³ + 9a² + 45a + 6ab² + 18b² → C

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The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May her driving cost was $380 for 48
andrezito [222]

Answer:

y=0.2x+284

Step-by-step explanation:

Let  x be the distance driven, d-distance and C our constant.

Our information can be presented as:

y=mx+c\\\\450=830x+C\ \ \ \ \ \ \ \ \ eqtn 1\\\\380=480x+C\ \ \ \ \ \ \ \ \ eqtn 2

#Subtracting equation 2 from 1:

70=350x\\x=0.2

Hence the fixed cost per mile driven,x is $0.20

To find the constant,C we substitute x in any of the equations:

450=830x+C\ \ \ \ \ \ \ X=0.2\\\therefore C=450-830\times0.2\\=284

Now, substituting our values in the linear equation:

y=0.2x+284       #y=cost of driving, x=distance driven

Hence the linear equation for the cost of driving is y+0.2x+284

7 0
3 years ago
Ayumi plans to go blueberry piking before school, which starts at 8:00 am the amount of blueberries B, in cups that alum picks g
Trava [24]

Answer:

M(t) = M(16 - 2·t)

Step-by-step explanation:

The function is just formed by using the concept of composite functions.

B is cups of blueberries, and n is cups of blueberries,

So by substituting values the required equations formed are given by :

B(t) = 2·(8 - t)  

M(n) = 12·n  

n = B(t)  

M(t) = M(n)

       = M(B(t))

       = M(2·(8 - t))

       = M(16 - 2·t)

Therefore, this is the required function muffins M

3 0
3 years ago
Read 2 more answers
What are the domain and range of the function f(x)=-3(x-5)squared+4
svet-max [94.6K]
Domain is all real numbers
range
hmm
we know that x^2=a positive number
then multiply it by that negative -3
therefor the range is going to be mostly negative
if we make the x-5  equal to zero, then there is no negative, so
wher x=5, then f(5)=0+4=4
the highest positive number you can get is f(5)=4

so therfor

domain=all real number
range is x≤4
6 0
3 years ago
Which of the following statements is true about the quadratic function f(x) = ax2 + bx + c?
Dahasolnce [82]

Answer:

A

Step-by-step explanation:

A. The constants a, b, and c must be real numbers with a not ever equal to zero.

Please vote brainliest <3

6 0
2 years ago
Ima need help on this one pls do quick
pshichka [43]

Answer:

65

Step-by-step explanation:

The area of the square is 5^2=25 and the area of a single triangle is \frac{1}{2}(5)(4)=10.

The total area is the square plus the 4 triangles 25+4(10)=65

4 0
1 year ago
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