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3 years ago

What is the product of a+3 and -2a2+15a+6b2

Mathematics

2 answers:

vitfil [10]3 years ago

6 0

Answer:

-2a³+ 9a² + 45a +6ab² + 18b².

Step-by-step explanation:

Given : a+3 and -2a²+15a+6b².

To find : what is the product.

Solution : We have given

(a+3)( -2a²+15a+6b²).

Distributes a over (-2a²+15a+6b²) and 3 over (-2a²+15a+6b²).

a (-2a²+15a+6b²) + 3 ( -2a²+15a+6b²).

-2a³+15a²+6ab² - 6a²+ 45a + 18b².

Combine like terms

-2a³- 6a² + 15a² + 45a +6ab² + 18b².

-2a³+ 9a² + 45a +6ab² + 18b².

Therefore, -2a³+ 9a² + 45a +6ab² + 18b².

DaniilM [7]3 years ago

3 0

Answer:

The third option

Step-by-step explanation:

Given

(a + 3)(- 2a² + 15a + 6b²)

Each term in the second factor is multiplied by each term in the first factor, that is

a(- 2a² + 15a + 6b²) + 3(- 2a² + 15a + 6b²) ← distribute both parenthesis

= - 2a³ + 15a² + 6ab² - 6a² + 45a + 18b² ← collect like terms

= - 2a³ + 9a² + 45a + 6ab² + 18b² → C

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A math professor notices that scores from a recent exam are normally distributed with a mean of 61 and a standard deviation of 8

Alexeev081 [22]

Answer:

a) 25% of the students exam scores fall below 55.6.

b) The minimum score for an A is 84.68.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 61 and a standard deviation of 8.

This means that $\mu = 61, \sigma = 8$

(a) What score do 25% of the students exam scores fall below?

Below the 25th percentile, which is X when Z has a p-value of 0.25, that is, X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 61}{8}$

$X - 61 = -0.675*8$

$X = 55.6$

25% of the students exam scores fall below 55.6.

(b) Suppose the professor decides to grade on a curve. If the professor wants 0.15% of the students to get an A, what is the minimum score for an A?

This is the 100 - 0.15 = 99.85th percentile, which is X when Z has a p-value of 0.9985. So X when Z = 2.96.

$Z = \frac{X - \mu}{\sigma}$

$2.96 = \frac{X - 61}{8}$

$X - 61 = 2.96*8$

$X = 84.68$

The minimum score for an A is 84.68.

8 0

3 years ago

425×7%×5<br>what the answer

VikaD [51]

The answer to your question is 148.75

5 0

3 years ago

Read 2 more answers

20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!

deff fn [24]

Answer: see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

x = 1.0, C(x) = 39

x = 1.1, C(x) = 63

x = 2.5, C(x) = 87

x = 3.0, C(x) = 87

x = 4.8, C(x) = 135

x = 5.0, C(x) = 135

x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

3 0

3 years ago

-1,2,5,7...with these numbers while using multiplaction, divison, addition, and subtraction, how would u get positive 24

baherus [9]

By adding two positives together, or a big positive number with a small negative number.

4 0

3 years ago

Please help me figure this out

katrin2010 [14]

Step-by-step explanation:

standard form is given by Ax × By = C

hence the answer would be

5x + 8y = 24

comment if you still have any doubts :)

3 0

2 years ago

Read 2 more answers