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8090 [49]
1 year ago
9

Consider the equation showing the distributive property 84+93=3(28+□)

Mathematics
1 answer:
arlik [135]1 year ago
4 0
Distributive property

We have that the distributive property states that the multiplication is done for all the terms inside the parenthesis. Then we have:

Since

3 · 28 = 84

and

3 · □ = 93

Since 3 · 31 = 93, then

□ = 31

<h2>Answer: 31</h2>

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Given Q is between J and K, JQ is five times the length of JK and JK=42 find the length of JQ
Alex73 [517]

Answer:

210

Step-by-step explanation:

JQ is 5 times the length of JK

● JQ = 5JK

JK = 42

● JQ = 5 × 42

● JQ = 210

8 0
3 years ago
Solve for x<br><br> x2 + 14x + 49 = 0
Allisa [31]
-3.0625 is the answer to x
4 0
3 years ago
The distribution of the annual incomes of a group of middle management employees approximated a normal distribution with a mean
kondor19780726 [428]

Answer:

68% of the incomes lie between $36,400 and $38,000.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  $37,200

Standard Deviation, σ = $800

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Empirical rule:

  • Almost all the data lies within three standard deviation of mean for a normally distributed data.
  • About 68% of data lies within one standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within three standard deviation of mean.

Thus, 68% of data lies within one standard deviation.

\mu \pm \sigma\\=37200 \pm 800\\=(36400,38000)

Thus, 68% of the incomes lie between $36,400 and $38,000.

5 0
3 years ago
I needa an answer?! It would really help &lt;3 <br><br><br> Thank you a lot!!!
Zarrin [17]

Answer:

C. 2.865

Step-by-step explanation:

All you have to do in this situation is to subtract the amount he ran two weeks ago by the amount Thomas ran last week. It would look like so,

38.074 - 35.209

And once you do that you get the answer of 2.865

Hope that helps and have a great day!

6 0
3 years ago
I need help with my homework .... It is passed due I have to get it done. If not I will get a F on it ... Please help me with it
Yuki888 [10]

a) see attachment for graph

b) D: [0, 2.5]    <em>time cannot be negative so the x-values start at 0</em>

   R: [0, 100]    <em>height cannot be negative so the y-values start at 0</em>

c) 84 ft             <em>refer to the red coordinate on the graph</em>

d) 1.75 seconds   <em>refer to the blue coordinate on the graph</em>

e) 2.5 seconds     <em>refer to the green coordinate on the graph</em>

<em />

When looking for coordinates at the various given values, remember that x is time and y is height.  

  • If you are given time, then look at the y-value for height
  • If you are given height, then look at the x-value for the time.

<em />

4 0
3 years ago
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