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Sergeu [11.5K]
2 years ago
6

Which function has real zeros at x = 3 and x = 7

Mathematics
1 answer:
iren2701 [21]2 years ago
7 0

Answer:

7

Step-by-step explanation:

okay

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Solve. (K+1)(k-5)=0<br> Explin how to solve ???
Anna71 [15]
Alright remember, if any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0. 
k+1=0
k-5=0
Set the first factor equal to 0 and solve
k=-1
Set the next factor equal to 0 and solve
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The final solution is all the values that make (k+1)(k-5)=0 true. 
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Hope this helped you out :)
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Answer and Step-by-step explanation:

The computation is shown below;

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The same is to be considered

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