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Gwar [14]
1 year ago
8

Which of the following graphs represents a function that has a positive

Mathematics
1 answer:
Karolina [17]1 year ago
7 0

Answer:

b , d

Step-by-step explanation:

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Use summation notation to express each of the following calculations Add the scores and square the sum O 2(SX) Square each score
iragen [17]

a)

Add the score and then square the sum.

By using the summation notation we can write the above statement is (Σx)²

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Square each score and then add the squared values.

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Subtract 2 point from each score and then add the resulting values.

By using the summation notation we can write the above statement is  Σ(x-2)

Subtract 1 point from each score and square the resulting values. Then add the squared values.

By using the summation notation we can write the above statement is Σ(x-1)²

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Antonio used 16 1/3 cups of flour to make banana bread. The recipe for one loaf of banana bread calls for 2 1/3 cups of flour. W
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3. 49 points in 7 games ​
tankabanditka [31]

Answer:

What do u mean

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The first step of a staircase that leads to an outdoor deck is above a concrete slab. The height, h, in centimeters of the n ste
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Point p(a,b) is in the first quadrant on the graph of the line x+y=4. A triangular region is shown on the diagram. What is the m
Gala2k [10]

Answer:

The maximum area of the triangular region is 2 square units

Step-by-step explanation:

we know that

The area of the triangular region is equal to

A=\frac{1}{2}(x)(y) -----> equation A

where

x is the x-coordinate of point P

y is the y-coordinate of point P

we have

The equation of the graph of the line is

x+y=4

y=-x+4 -----> equation B

substitute equation B in equation A

A=\frac{1}{2}(x)(-x+4)

A=-\frac{1}{2}x^2+2x

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The y-coordinate of the vertex represent the maximum area of the triangular region

Find the vertex

Convert the quadratic equation in vertex form

Factor -1/2

A=-\frac{1}{2}(x^2-4x)

Complete the square

A=-\frac{1}{2}(x^2-4x+4)+2

Rewrite as perfect squares

A=-\frac{1}{2}(x-2)^2+2

The vertex is the point (2,2)

so

The maximum area is the y-coordinate of the vertex

The maximum area of the triangular region is 2 square units

Find the coordinates of point P for the maximum area

x=2 (x-coordinate of the vertex)

Find the y-coordinate of point P

substitute in equation B

y=-2+4=2

The coordinates of point P for the maximum area is P(2,2)

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