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Yuri [45]
3 years ago
14

Which line is perpendicular to y = 2x?

Mathematics
2 answers:
DiKsa [7]3 years ago
6 0
1/2 x + 1 is perpendicular
Angelina_Jolie [31]3 years ago
5 0
The line y= -1/2x + 1 is perpendicular.
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Is absolute value of -998​
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Answer:

998.

Step-by-step explanation:

Just get rid of the negative sign

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Triangle A″B″C″ is formed by a reflection over x = −1 and dilation by a scale factor of 4 from the origin. Which equation shows
juin [17]

Answer:

\frac{AB}{A''B''}  = \frac{1}{4}

Step-by-step explanation:

Given the information:

  • A'B'C' reflection over x = −1
  • dilation by a scale factor of 4 from the origin

<=> the two triangles are similar to each other, triangles are similar if they have the same shape, but can be different sizes, so  A″B″C″ is 4 time bigger than ABC

=> the relationship between ΔABC and ΔA″B″C″

= \frac{AB}{A''B''}  = \frac{1}{4}

We choose C.

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3 years ago
Find the volume of a cone with the same radius and height as the cylinder belon. Explain how you found the
siniylev [52]

Answer:

Step-by-step explanation:

6 0
2 years ago
If the cos 30° = square root 3 over 2, then the sin 60° = _____. 0, because the angles are complementary 1 over 2, because the a
leva [86]
Well, the answer would be square root of 3 over 2 because of the unit circle. So, the answer choice should be which ever one involved square root 3 over 2
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3 years ago
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Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi
natta225 [31]

Answer:

b. circle; 2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0

Step-by-step explanation:

The given conic has equation;

x^2-5x+y^2=3

We complete the square to obtain;

(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}

This is a circle with center;

(\frac{5}{2},0)

This implies that;

x=\frac{5}{2},y=0

When the circle is rotated through an angle of \theta=\frac{\pi}{3},

The new center is obtained using;

x'=x\cos(\theta)+y\sin(\theta) and y'=-x\sin(\theta)+y\cos(\theta)

We plug in the given angle with x and y values to get;

x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3}) and y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})

This gives us;

x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}

The equation of the rotated circle is;

(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}

Expand;

(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}

Multiply through by 4; to get

4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37

Write in general form;

4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0

Divide through by 2.

2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0

8 0
3 years ago
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