9514 1404 393
Answer:
(3, 1)
Step-by-step explanation:
We assume you want the solution to the system ...
The second equation gives a nice expression for x, so we can use that in the first equation.
2(y+2) -3y = 3 . . . . substitute for x in the first equation
2y +4 -3y = 3 . . . . . eliminate parentheses
-y = -1 . . . . . . . . . . . collect terms, subtract 4
y = 1 . . . . . . . . . . . . multiply by -1
x = 1 +2 = 3 . . . . . . substitute for y in the second equation
The solution is (x, y) = (3, 1).
If you know that y = 6. You just have to switch Y by 6.
x + 2y = 16
x + 2*6 = 16
x + 12 = 16
x = 16 - 12
x= 4
4 + 2*6 = 16
Hope this helps !
Photon
Answer:
answer E
Step-by-step explanation:
Answer:
its 10 cuz 240 x 984 = 12009
Step-by-step explanation:
Answer:
Option C (f(x) = 
)
Step-by-step explanation:
In this question, the first step is to write the general form of the quadratic equation, which is f(x) = 
, where a, b, and c are the arbitrary constants. There are certain characteristics of the values of a, b, and c which determine the nature of the function. If a is a positive coefficient (i.e. if a>0), then the quadratic function is a minimizing function. On the other hand, a is negative (i.e. if a<0), then the quadratic function is a maximizing function. Since the latter condition is required, therefore, the first option (f(x) = 
) and the last option (f(x) = 
) are incorrect. The features of the values of b are irrelevant in this question, so that will not be discussed here. The value of c is actually the y-intercept of the quadratic equation. Since the y-intercept is 4, the correct choice for this question will be Option C (f(x) = ). In short, Option C fulfills both the criteria of the function which has a maximum and a y-intercept of 4!!!
