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german
1 year ago
10

Mrs Smith is completing a mathematics problem. She knows when 6 is added to four times a number, the result is 50. What would be

the equation she should write to begin her work?
Mathematics
1 answer:
Lesechka [4]1 year ago
6 0

EXPLANATION:

-To formulate an equation, you must first know what data the exercise gives us to locate them correctly.

data:

-6 that must be added to a number.

-four times a number that is equal to 4x

-a result that is equal to 50

Now with these data we formulate the equation:

\begin{gathered} \text{Equation:} \\ 6+4x=50;\text{  } \end{gathered}

if we solve the equation we have:

\begin{gathered} 6\text{ }+4x=50 \\ 4x=50-6 \\ 4x=44 \\ x=\frac{44}{4} \\ x=-\frac{22}{2} \\ x=\text{ }-11 \end{gathered}

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8x –3(5x–2)=7–10x <br><br> Solve this equation with a clear value for x
Serga [27]

Answer:

x = 1/3

Step-by-step explanation:

8x –3(5x–2)=7–10x

Distribute

8x - 15x +6 = 7-10x

Combine like terms

-7x + 6 = 7- 10x

Add 10x to each side

-7x +10x+ 6 = 7- 10x+10x

3x+6 = 7

Subtract 6 from each side

3x+6-6 =7-6

3x = 1

Divide each side by 3

3x/3 = 1/3

x = 1/3

8 0
3 years ago
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PROVE THESE TRIANGLES ARE CONGRUENT
jenyasd209 [6]

Answer:

These triangles cannot be proved congruent

Step-by-step explanation:

The theorems for congruence are  SSS SAS ASA AAS. Here, there is only one common side and one common angle marked, therefore you cannot prove congruency.

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2 years ago
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A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the
Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

             P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample average age = 25 years

            \sigma = population standard deviation = 1.8 years

            n = sample of students = 36

            \mu = population average age

So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

                                                  = [ 25 - 2.3263 \times {\frac{1.8}{\sqrt{36} } , 25 + 2.3263 \times {\frac{1.8}{\sqrt{36} } ]

                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0
3 years ago
Circle the following 2 terms that correspond with the domain of a function:
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Answer:

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8 0
3 years ago
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Subtract 3/5p from both sides:
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Subtract 2/5 from both sides:
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2/5p = 2/5

Multiply both sides by 5/2

(5/2) * (2/5p) = (5/2) * (2/5)

p  =  1


Answer:  p  =  1





Hope that helps!!! (Answer:   Letter Choice (A),  p  =  1







8 0
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