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1 year ago

PROVE THESE TRIANGLES ARE CONGRUENT

Mathematics

2 answers:

jenyasd209 [6]1 year ago

8 0

Answer:

These triangles cannot be proved congruent

Step-by-step explanation:

The theorems for congruence are SSS SAS ASA AAS. Here, there is only one common side and one common angle marked, therefore you cannot prove congruency.

disa [49]1 year ago

3 0

Answer: They are congruent

Step-by-step explanation:

The side marks are marked as 1, so they are equal. You can try moving the second triangle on the first, but what you can also do is use the law of cosines using a random side and angle value to find if the other sides are equivalent.

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A standard deck of 52 cards theses cards are divided into four 13-suits: hearts, clubs, spades, and diamonds find the possibilit

Nikitich [7]

24/52 because there are 6 even number in a 13 card section

2,4,6,8,10,12

and there are four of them so you multiply 6 by 4 to get 24

since you know there are 52 cards then you will place 24 over 52

you can simplify this fraction to 6/13 depending what you want

8 0

3 years ago

Simplify square root of 1008 ( V` Represents the square root sign.)

Alexus [3.1K]

So first factor it
1008=2*2*2*2*3*3*7
group them in similar pairs
1008=(2*2)(2*2)(3*3)*7
now remember we can do
$\sqrt{xy}= \sqrt{x} \sqrt{y}$ so
$\sqrt{1008}= (\sqrt{2*2}) (\sqrt{2*2}) (\sqrt{3*3}) (\sqrt{7})$ =
2*2*3* $\sqrt{7}$ =
12√7

the answer is B

5 0

2 years ago

Is this statement true or false explain why 6,203 > 6,320

harina [27]

Answer:

false

Step-by-step explanation:

3 0

2 years ago

The measures of angles of a triangle are shown in the figure below solve for

irina1246 [14]

Answer:

x=51

Step-by-step explanation:

There are two ways you can go about this

You can either say that the sum of interior angles in a triangle is equal to 180 so you do 180-39-90=51

Or you could use the exterior angle theorem, which means that 90=39+x, simplify that and you get that x=51

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2 years ago

The equation of a circle whose center is at ( 4,0 ) and radius is length 2 ( square root ) 3

Vesna [10]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the center
r - the radius

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$(x-4)^2+(y-0)^2=(2\sqrt{3})^2 \\
\boxed{(x-4)^2+y^2=12}$

8 0

2 years ago

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