Answer:
A. 0.5
B. 0.32
C. 0.75
Step-by-step explanation:
There are
- 28 students in the Spanish class,
- 26 in the French class,
- 16 in the German class,
- 12 students that are in both Spanish and French,
- 4 that are in both Spanish and German,
- 6 that are in both French and German,
- 2 students taking all 3 classes.
So,
- 2 students taking all 3 classes,
- 6 - 2 = 4 students are in French and German, bu are not in Spanish,
- 4 - 2 = 2 students are in Spanish and German, but are not in French,
- 12 - 2 = 10 students are in Spanish and French but are not in German,
- 16 - 2 - 4 - 2 = 8 students are only in German,
- 26 - 2 - 4 - 10 = 10 students are only in French,
- 28 - 2 - 2 - 10 = 14 students are only in Spanish.
In total, there are
2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.
The classes are open to any of the 100 students in the school, so
100 - 50 = 50 students are not in any of the languages classes.
A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is

B. If a student is chosen randomly, the probability that he or she is taking exactly one language class is

C. If 2 students are chosen randomly, the probability that both are not taking any language classes is

So, the probability that at least 1 is taking a language class is

Answer:
steps below
Step-by-step explanation:
arc QR = 2x57 - 41 = 73
arc PQ = 360 - 73 - 41 - 137 = 109
m∠Q = (41+137) / 2 = 89°
m∠R = (109+137) / 2 = 123°
m∠S = (109+73) / 2 = 91°
check: ∠R+∠p = 123+57 = 180
∠Q+∠S = 89+91 = 180
Answer:
If her brother has 40 tickets, the equation will be 3(40)+2=122. jamie will have 122 tickets
If her brother has 50 tickets, the equation will be 3(50)+2=152. jamie will have 152 tickets
If her brother has 60 tickets, the equation will be 3(60)+2= 182. jamie will have 182 tickets.
Step-by-step explanation:
Just trust me
#3. Plugging the point (3,0) into any of the equations except the third one gives an invalid answer.
√42 -- 6.48074069841
√150 -- 12.2474487139
√245 -- 15.6524758425
√398 -- 19.9499373433
Hope it helps... pls mark brainliest