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yarga [219]
1 year ago
10

How do you graph 10.50a+7.50c=141

Mathematics
1 answer:
Anastaziya [24]1 year ago
8 0

Using the x-intercept and y-intercept of the equation, the graph of the equation is shown below

From the question, we are to graph the given equation

The given equation is

10.50a + 7.50c = 141

To graph the line, we will plot the variable a on the x-axis and the variable c on the y-axis of the cartesian plane.

Now, we will the determine the x-intercept and the y-intercept.

The x-intercept is the point where c = 0; and y-intercept is the point where a = 0

Determine the x-intercept

10.50a + 7.50c = 141

10.50a + 7.50(0) = 141

10.50a  = 141

a = 141/10.50

a = 13.43

The x-intercept is (13.43, 0)

Determine the y-intercept

10.50(0) + 7.50c = 141

7.50c = 141

c = 141/7.50

c = 18.80

The y-intercept is (0, 18.80)

Hence, using the x-intercept and y-intercept of the equation, the graph of the equation is shown below

Learn more on Graph of equations here: brainly.com/question/4074386

#SPJ1

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What is the area of this composite shape?<br> Enter your answer in the box.
bonufazy [111]

Answer:

The answer to your question is:  53 in²

Step-by-step explanation:

Area = ?

Process: divide the shape in one rectangle and one triangle.

Area of rectangle

                            A = base x height

                            A = 8 x 6

                            A = 48 in²

Area of rectangle

                          base = 13 - 8

                                   = 5 in

                          height = 6 - 4

                                     = 2 in

                          Area = (b x h) / 2

                                   = (5 x 2) / 2

                                   = 10 / 2

                                   = 5 in²

Total area = 48 + 5 = 53 in²

3 0
3 years ago
H(t)= (t+3)^2 + 5
oee [108]

Answer:

The average rate of change for the given function in the interval (-5, -1) is 0 (zero)

Step-by-step explanation:

The average rate of change of a function over an interval is the quotient between the difference between the function evaluated at the ends of the interval divided by the length of the interval. That is for our case:

the average rte of change of h(t) in the interval (-5, -1) is:

\frac{h(-1)-h(-5)}{-1+5}

so we find:

h(-1)=(-1+3)^2+5=2^2+5=4+5=9\\and\\h(-5)=(-5+3)^2+5=(-2)^2+5=4+5=9

then the average rate of change becomes:

\frac{h(-1)-h(-5)}{-1+5}=\frac{9-9}{4} =\frac{0}{4} =0

5 0
2 years ago
Whats (c-7)(c+5) , (double brackets)
kherson [118]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

let's evaluate :

  • (c - 7)(c + 5)

  • {c}^{2}  + 5c - 7c - 35

  • {c}^{2}  - 2c - 35
6 0
2 years ago
Read 2 more answers
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