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3 years ago

Select all the equations on which the point (10, 0) lies.

Mathematics

1 answer:

lilavasa [31]3 years ago

5 0

Answer:

The answer to this problem is B, C, and E.

Step-by-step explanation:

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Round 29.315 to the nearest hundredth

castortr0y [4]

Answer:

29.32

Step-by-step explanation:

sense 1 is the hundredth you just round now so 5 is big enough so it would make the hundreth number go up by 1.

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3 years ago

I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Savatey [412]

Answer:

f(x) = g(x-9)

Step-by-step explanation:

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2 years ago

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The perimeter of a square picture frame is 24 in. Find the lengths of each side of the frame.

m_a_m_a [10]

Answer:

6 inches

Step-by-step explanation:

The perimeter formula for a square is P = 4*S

P =24

s = ?

24 = 4*S Divide both sides by 4

24/4 = 4S/4

S = 6

6 0

2 years ago

Read below i need some help please

Anton [14]

Answer:

8/20

Step-by-step explanation

boys left handed=3

boys right handed=9

girls left handed=2

girls right handed=6

what is the probability that a student chosen from random is a girl? give answer as a fraction please and include step by step process

girls left handed: 2

girls right handed: 6

6+2=8

total all students 20

8/20

4 0

3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago