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ddd [48]
2 years ago
14

Please help with parts (a), (b),and (c).No need much explanation

Mathematics
1 answer:
fomenos2 years ago
5 0

Given the Histogram that summarizes the data obtained by Kemala:

(a) The Class Width is the length of the intervals.

In order to find the Class Width, you need to subtract the lowest value of each bar from the lowest value of the previous bar.

In this case, you get:

\begin{gathered} 5-2=3 \\ 8-5=3 \\ 11-8=3 \end{gathered}

Therefore:

Class\text{ }Width=3

(b) You need to identify the number of beaches that had 10 or fewer pregnant turtles. Therefore, you need to add the corresponding number of beaches that correspond to these bars (A, B and C):

Then, you get:

3+8+4=15

(c) You can identify that the interval of the last bar is from 11 to 13, and the number of beaches that corresponds to that bar is:

6

As you can see below

Hence, the answers are:

(a)

3

(b)

15

(c)

6

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Step-by-step explanation: the probability mass function that defines a possion probability distribution is given below as

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For this question, x = 0 and u = 9.5

Hence we have that

P(x=0) = e^-0 × 9.5^0 / 0!

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3 years ago
Five less than half of a number in a equation
Sholpan [36]

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Please help with actual steps, and don’t reply w nonsense just for the points. Thank you !!!
Anton [14]

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1. 24x^6

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5. 90x^5y^6

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3 years ago
How many ways can you make change for a $50 bill using $5, $10, and $20 bills?
aleksley [76]

Answer:

There are 12 ways to make change for a $50 bill using $5, $10 and $20 bills

Step-by-step explanation:

Let's write down every possibility starting by using the largest quantity of $20 bills and we'll go from there, everytime that we get a $10 bill we will split it in the next option into 2 $5 bills.

(20)(20)(10)

(20)(20)(5)(5)

(20) (10)(10)(10)

(20)(10)(10)(5)(5)

(20)(10)(5)(5)(5)(5)

(20)(5)(5)(5)(5)(5)(5)

Now we start with the largest quantity of $10 bills (5) and go from there, splitting them into two 5 dollar bills in the next option.

(10)(10)(10)(10)(10)

(10)(10)(10)(10)(5)(5)

(10)(10)(10)(5)(5)(5)(5)

(10)(10)(5)(5)(5)(5)(5)(5)

(10)(5)(5)(5)(5)(5)(5)(5)(5)

(5)(5)(5)(5)(5)(5)(5)(5)(5)(5)

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3 years ago
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