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Lelu [443]
1 year ago
9

Herr is a balance hanger diagram a circle has a mass of three grams and a square has a mass of two grams which is the mass of th

e triangle 1 pt
Mathematics
1 answer:
Naily [24]1 year ago
3 0

The hanger diagram ideally should be in balance with all the shapes hung on it.

On the left side, it shows that the circles are 9 grams and the squares are 12 grams. The triangles are 2t grams. Therefore, on the left side we have,

9 + 12 + 2t

On the right side, it shows the circles are 6 grams and the squares are 6 grams, while the triangles are 5t grams. Therefore on the right side we have

6 + 6 + 5t.

For the hanger to be in balance, we should have

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Which of the following statements is supported by Chargaff's rule about the composition of DNA?
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The number of adenine sim a strand of DNA is equal to the number of thymines.
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Rui is a professional deep water free diver.
Arada [10]

Answer:

Rui will reach his lowest altitude after diving for 10 seconds

Step-by-step explanation:

In the quadratic equation y = ax² + bx + c, the coordinates of the lowest or the highest point is (h, k), where

  • h = \frac{-b}{2a} and k = y at x = h

In the given question

∵ d(x) = \frac{1}{2} x² - 10 x

∵ d represents his altitude in meters after x seconds

→ Compare it with the form above to find a and b

∴ a =  \frac{1}{2} and b = -10

∵ h = \frac{-b}{2a}

→ Substitute the values of a and b in the rule to find h

∴ h = \frac{--10}{2.\frac{1}{2}} = 10

∴ h = 10

∵ h is the x-coordinate of the lowest point

∴ The time of the lowest altitude is 10 seconds

∴ Rui will reach his lowest altitude after diving for 10 seconds

5 0
3 years ago
Read 2 more answers
Given two independent random samples with the following results: n1=8x‾1=186s1=33 n2=7x‾2=171s2=23 Use this data to find the 90%
KonstantinChe [14]

Answer:

The point of estimate for the true difference would be:

186-171= 15

And the confidence interval is given by:

(186-171) -1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= -10.753

(186-171) +1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= 40.753

Step-by-step explanation:

For this case we have the following info given:

\bar X_1 = 186 the sample mean for the first sample

\bar X_2 = 171 the sample mean for the second sample

s_1 =33 the sample deviation for the first sample

s_2 =23 the sample deviation for the second sample

n_1 = 8 the sample size for the first group

n_2 = 7 the sample size for the second group

The confidence interval for the true difference is given by:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

We can find the degrees of freedom are given:

df = n_1 +n_2 -2 =8+7-2= 13

The confidence level is given by 90% so then the significance would be \alpha=1-0.9=0.1 and \alpha/2=0.05 we can find the critical value with the degrees of freedom given and we got:

t_{\alpha/2}= \pm 1.77

The point of estimate for the true difference would be:

186-171= 15

And replacing into the formula for the confidence interval we got:

(186-171) -1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= -10.753

(186-171) +1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= 40.753

5 0
3 years ago
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