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STatiana [176]
2 years ago
7

Eleven members of the Middle School Math Club each paid the same amount for a guest speaker to talk about problem solving at the

ir math club meeting. They paid their guest speaker $1−A−2−$1_A_2_. What is the missing digit AA of this 33-digit number?
Mathematics
1 answer:
tiny-mole [99]2 years ago
7 0
The missing digit is number 3. The total amount should be $132

I multiplied 11 by the numbers 10 and above to get the possible three digit answer who has 1 as the first digit and 2 as the last digit.

11 x 10 = 110
11 x 11 = 121
11 x 12 = 132

The 11 members of the Middle School Math club each paid $12 for a guest speaker.
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Two angles of a triangle have measures of 75and 62 degrees . What is the measure of the third angle?
777dan777 [17]

9514 1404 393

Answer:

  D. 43 degrees

Step-by-step explanation:

The sum of angles in a triangle is 180°. If x represents the measure of the third angle, then ...

  75° +62° +x = 180°

  137° +x = 180° . . . . . . . . . collect terms

  x = 180° -137° = 43° . . . . subtract 137° from both sides of the equation

The third angle measures 43°.

4 0
2 years ago
Which expression is equivalent
RUDIKE [14]

Given expression is

\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}

Radical is fourth root

first we simplify the terms inside the radical

\frac{x^{11}}{x^7}=x^4

\frac{y^(8)}{y^6}=y^2

So the expression becomes

\sqrt[4]{\frac{16x^4y^2}{81}}

Now we take fourth root

\sqrt[4]{16} = 2

\sqrt[4]{81} = 3

\sqrt[4]{x^4} = x

We cannot simplify fourth root (y^2)

After simplification , expression becomes

\frac{2x\sqrt[4]{y^2}}{3}

Answer is option B


7 0
3 years ago
Find the volume of the solid where the cone and half sphere are hollow. Use 3.14 for П ; height is 19 in; radius is 5 in. Round
Vera_Pavlovna [14]

Volume of Solids

The volume of the solid is 758.83 in³

Step-by-step explanation:

Given that the cone and half sphere is hollow

The volume of the cone = 1/3 \pi r^{2} h\\

The Volume of the sphere  = 4/3 \pi r^{3}

So the Volume of the half sphere =2/3\pi r^{3}

The volume of solid = volume of cone + volume of the half sphere

V = V_{1}  + V_{2}

Given

height h = 19 in

radius r = 5 in

V_{1\\}  = 1/3 \pi r^{2} h

     = 1/3 × 3.14 × 5 × 5 × 19

     = 497.16 in³

V_{2}  =  2/3 \pi r^{3}

   = 2/3 × 3.14 × 5 × 5 × 5

   = 261.67 in³

V =  497.16 in³ + 261.67 in³

  = 758.83 in³

Hence the volume of the solid is 758.83 in³

3 0
3 years ago
Solve for x. Round to the nearest tenth, if necessary.
blsea [12.9K]

Answer:

ST = x = 1.8 (to the nearest tenth)

Step-by-step explanation:

STU is a right triangle right angled at T with S =61° and hypotenuse SU=3.7 units.

ST = x = SUcos(61°) = 3.7cos(61°) = 3.7*0.48481 = 1.7938

6 0
3 years ago
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Answer:

Graph A

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look at a site called marhway.com

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