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MA_775_DIABLO [31]
1 year ago
13

Find the volume of a cube? 8 inches

Mathematics
1 answer:
kozerog [31]1 year ago
5 0

A cube has all it sides equal.

The volume of a cube is given by Length x Length x Length

\begin{gathered} Volume=8X8X8inches^3 \\ \text{Volume = 512 inches }^3 \end{gathered}

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5 0
3 years ago
Write an equation in slope-intercept form of the line that passes through (-5, 19) and (5.13).
ruslelena [56]

Answer:

y=-3/5x+16

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(13-19)/(5-(-5))

m=-6/(5+5)

m=-6/10

simplify

m=-3/5

y-y1=m(x-x1)

y-19=-3/5(x-(-5))

y-19=-3/5(x+5)

y=-3/5x-15/5+19

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3 0
3 years ago
Write 8.87 as a mixed number and as an improper fraction.<br> Do not try to simplify your answers.
kodGreya [7K]

Answer:

  8 87/100 = 887/100

Step-by-step explanation:

"Eight and eighty-seven hundredths" is ...

  8 87/100 = 887/100

4 0
3 years ago
Read 2 more answers
Bill Gates wrote a computer program that generates three random numbers
Allushta [10]

Answer:

1/1000

Step-by-step explanation:

The probability of two independent events A, B (independent = events that do not depend on each other) is given by the product of the individual probabilities of A and B:

p(AB)=p(A)\cdot p(B) (1)

In this problem, the single event is "getting a 3" when extracting a random number between 1 and 10.

The total number of possible outcomes is

n = 10

While the number of succesfull outcomes (getting a 3) is only one:

s=1

So, the probability of drawing a 3 in 1 draw is

p(3)=\frac{s}{n}=\frac{1}{10}

Then, we want to find the probability of getting three "3" in 3 consecutive generations. These events are independent events, so we can use rule (1) to find the total probability, and we get:

p(333)=p(3)p(3)p(3)=(\frac{1}{10})(\frac{1}{10})(\frac{1}{10})=\frac{1}{1000}

7 0
3 years ago
Neptunes average distance from the sun is 4.503x10^9 km. Mercurys average distance from the sun is 5.791x10^7 km. About how many
LuckyWell [14K]
Neptune is 77.76 times farther from the Sun than Mercury is. 


6 0
3 years ago
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