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Vitek1552 [10]
4 years ago
13

The graph that is made up of two straight lines, which has an absolute maximum or absolute minimum, and is symmetric belongs to

the
function family.

Mathematics
1 answer:
Radda [10]4 years ago
6 0

Answer:

This may be a function of the absolte value family.

f(x) = IxI.

f(x) = x if x ≥ 0

f(x) = -x  if x ≤ 0

Where this is the parent function, and the graph is shown below in green.

If the coefficient is positive, then the lines open upwards, and we will have a minimum (in this case, when x = 0).

And also in this case, we have symmetry around the value x = 0.

Now, the vertex can also be an absolute maximum if the coefficient is negative, like in the example shown below in color blue (the equation for the blue graph is f(x) = -3*IxI )

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3 years ago
Write a linear function from the given values: <br><br> f(2)=-2, f(1)=1<br><br><br> f(4)=1, f(8)=4
kap26 [50]

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have:

f(2)=-2\to(2,\ -2)\\f(1)=1\to(1,\ 1).

Substitute:

m=\dfrac{1-(-2)}{1-2}=\dfrac{3}{-1}=-3

Therefore we have y=-3x+b.

Substitute the coordinates of the point (1, 1) to the equation:

1=-3(1)+b

1=-3+b      <em>add 3 to both sides</em>

4=b\to b=4

<h3>Answer: y = -3x + 4</h3>

We have:

f(4)=1\to(4,\ 1)\\f(8)=4\to(8,\ 4)

Substitute:

m=\dfrac{4-1}{8-4}=\dfrac{3}{4}

Therefore we have y=\dfrac{3}{4}x+b.

Substitute the coordinates of the point (4, 1) to the equation:

1=\dfrac{3}{4}(4)+b

1=3+b      <em>subtract 3 from both sides</em>

-2=b\to b=-2

<h3>Answer: y=\dfrac{3}{4}x-2</h3>
3 0
4 years ago
Neeed Help ASAP Quick
Andrew [12]

Answer:

4; 7

Step-by-step explanation:

Small box = 25 and Large box = 50

small box = x and large box = x+3

25x+50(x+3)=450

25x+50x+150=450

75x=300

x=4

Large box = 4+3 = 7

Therefore, 4; 7

I hope this helped and have a good rest of your day!

3 0
3 years ago
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