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tia_tia [17]
2 years ago
13

Someone pls help solve this

Mathematics
2 answers:
mars1129 [50]2 years ago
8 0

Answer:

Look above

Step-by-step explanation:

Hopr it helps

Verizon [17]2 years ago
3 0

Answer:

answer is 2

hope it helps you please mark me as brainlist

Step-by-step explanation:

4×5y=10(y+2)

20y=20+10y

20y-10y=20

10y=20

y=20÷10

y=2

❥❥❥❥╬٨ـﮩ❤️itzmrsshayar❤️ـﮩﮩـ╬❥❥❥❥

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In the number below, what happens to the value of the digit 3 when it is moved one place value to the left?
Elis [28]

Answer:

it increases by a factor of 10, hence option B is the answer

Step-by-step explanation:

Initial Figure = 2037

When it is moved one place to the left, it increases from tens to hundreds

Hence option B is the answer

5 0
3 years ago
At a party, there are 2 six-packs of regular cola, 1 six-pack of diet cola, 1 six-pack of cherry cola, and 1 six-pack of vanilla
aliya0001 [1]

Answer:

B.

Step-by-step explanation:

There are 5 total 6-packs of cola. 1 is cherry and the other is vanilla. 2 out of 5 are the flavors. This means you have a 2 in 5 chance of getting a cherry or vanilla cola.

8 0
4 years ago
A full-grown giraffe is about 6 times heavier than a full-grown lion. A full-grown cheetah is about one-quarter as heavy as a fu
Angelina_Jolie [31]

Answer:

sorry i dont know

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
K-2k=15+1+6k-2 help me
sveticcg [70]
K - 2k = 15 + 1 + 6k - 2

-k = (15 + 1 - 2) + 6k

-k = 14 + 6k      |subtract 6k from both sides

-7k = 14    |divide both sides by (-7)

k = -2
6 0
3 years ago
The amount of time it takes for a student to complete a statistics quiz is uniformly distributed (or, given by a random variable
topjm [15]

Answer:

(A) 0.15625

(B) 0.1875

(C) Can't be computed

Step-by-step explanation:

We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.

Let X = Amount of time taken by student to complete a statistics quiz

So,   X ~ U(32 , 64)

The PDF of uniform distribution is given by;

    f(X) = \frac{1}{b-a} ,  a < X < b      where a = 32 and b = 64

The CDF of Uniform distribution is P(X <= x) = \frac{x-a}{b-a}

(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)

   P(X > 59) = 1 - P(X <= 59) = 1 - \frac{x-a}{b-a} = 1 - \frac{59-32}{64-32} = 1-\frac{27}{32} = 0.15625

(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43)  = P(X <= 43) - P(X < 37)

    P(X <= 43) = \frac{43-32}{64-32} = \frac{11}{32} = 0.34375

    P(X < 37) = \frac{37-32}{64-32} = \frac{5}{32} = 0.15625

    P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875

(C) Probability that student complete the quiz in exactly 44.74 minutes

     = P(X = 44.74)

The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.

3 0
4 years ago
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