Question

-Write the perimeter and area as an algebraic expression * Dyuda de Cools Add-ons The latest eEnglishBUUR- SpanishWrite the perimeter and area as an algebraic expression1) Write and simplify the perimeter of a square whose side is 4x - 2 inches.2) Write and simplify an algebraic expression for the area of a rectangle whose width is 6 feet and whose length is 3x + 1. Then, find the area if x = 2.5.3) The area of a rectangle is 8x - 12. The width is 4 feet. Find the length4) The perimeter of a rectangle is 4x + 14. The length is x + 5. Find the width.

Answer 1

$\begin{gathered} 1) \\ Perimeter=4\cdot L \\ L=4x-2 \\ \text{Perimeter =4}\cdot(4x-2) \\ \text{Perimeter = 16x-8} \\ 2) \\ A=length\cdot width \\ A=(3x+1)\cdot(6) \\ A=18x+6 \\ x=2.5 \\ A=18\cdot(2.5)+6 \\ A=45+6 \\ A=51 \\ 3) \\ A=length\cdot width \\ 8x-12=length\cdot(4) \\ length=\frac{8x-12}{4} \\ length=\frac{4(2x-3)}{4} \\ length=2x-3 \\ 4) \\ rec\tan gle´s\text{ perimeter=2}length+2width \\ 4x+14=2\cdot(x+5)+2width \\ 4x+14=2x+10+2width \\ 2width=4x+14-2x-10 \\ 2width=2x+4 \\ width=\frac{2x+4}{2} \\ width=\frac{2(x+2)}{2} \\ width=x+2 \end{gathered}$