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FromTheMoon [43]
3 years ago
8

If f(x)=3x²-7 and f(x+n)=3x²+24x+41, what is the value of n?

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0

Answer:

n=4

Step-by-step explanation:

f(x+n)=3(x+n)^2-7=3x^2+24x+41

3x^2+3n^2+6xn-7=3x^2+24x+41

Comparing and we will get, n=4

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(a^4(3a^2b)^3)/((3ab^2)^-1) exponent has to be postive and has to be simplified
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Ed

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In other words:

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