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2 years ago

Solve the equation for x. 4^5 square root (2x-4)^2=16

Mathematics

1 answer:

VMariaS [17]2 years ago

6 0

The value of x in the equation is 4

<h3>What are algebraic expressions?</h3>

Algebraic expressions are seen as expressions that consist of factors, variables, terms, coefficients, and certain constants.

These expressions are also known to be composed of some arithmetic operations, which includes;

Subtraction
Addition
Division
Multiplication
Parentheses
Bracket, etc

Given the expression;

(2x-4)^2=16

√(2x-4)^2 = 16

Find the square root of the expression, we have;

√(2x -4)^2= √16

Find the values

2x - 4 = 4

collect like terms

2x = 4 + 4

Add like terms

2x = 8

Make 'x' the subject of formula

x = 8/2

x = 4

Hence, the value is 4

Learn more about algebraic expressions here:

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3 years ago

4 + -6g + 10g + -5 anwser

Olegator [25]

Answer:

4g - 1

Step-by-step explanation:

4 and -5 are numbers

While, -6g and 10g are variables.

Add numbers and variable separately.

4 + -6g + 10g + -5

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

A closed box is constructed of 4200cm2 of cardboard. The box is a cuboid, with height hcm and square base of side xcm . What is

inysia [295]

Answer:

x is 10 $\sqrt{7}$

Step-by-step explanation:

Let x is the side of the base
Let h is the height

Given that:

The area A = 4200 cm2

<=> 2 $x^{2}$ + 4xh = 4200 cm2

<=> 4xh = 4200 - 2 $x^{2}$

<=> h = (4200 - 2 $x^{2}$ )/4x

The volume of the box:

V = $x^{2}$ h

<=> V = $x^{2}$ (4200 - 2 $x^{2}$ )/4x

<=> V = (4200x - 2 $x^{3}$ )/4

To find the maximum volume, we differentiate volume with respect to x:

dV/dx = (4200 - 6 $x^{2}$ )/4

Set dV/dx = 0, we have:

4200 - 6 $x^{2}$ =0

<=> $x^{2}$ = 700

<=> x = 10 $\sqrt{7}$

We differentiate again

d²V/dx² = -12x/4

It is negative so the volume is maximum.

So x is 10 $\sqrt{7}$

5 0

3 years ago