2.8a^2=55
a^2=55/2.8
a= square root of 55/2.8
9514 1404 393
Answer:
Step-by-step explanation:
The extrema will be at the ends of the interval or at a critical point within the interval.
The derivative of the function is ...
f'(x) = 3x² -4x -4 = (x -2)(3x +2)
It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...
f(0) = 2
f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6
f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1
The absolute maximum on the interval is f(0) = 2.
The absolute minimum on the interval is f(2) = -6.
Answer:
6x - 4
Step-by-step explanation:
f(x) + g(x)
= 4x + 8 + 2x - 12 ← collect liketerms
= 6x - 4
Answer:
0.85c
Step-by-step explanation:
To simplify the expression, subtract like terms:
c - 0.15c
= 0.85c
So, the simplified expression is 0.85c
Answer:
Total periodic pension costs (TPPC) is equal to the contributions plus change in the pension liability during the year. Each period, the periodic pension cost is recognized in profit or loss (P&L) and/or in other comprehensive income (OCI).