931 g of nitric acid is required to react with 454 g of C₇H₈ in the reaction between them.
<h3>What is stoichiometry ?</h3>
It refers to the relation between the amount of reactants and products. It is a quantitative study concerned with mainly numbers.It helps in utilizing the balanced chemical equations for calculating the quantity of reactants and products.
The reaction between nitric acid and C₇H₈ takes place as follows:
C₇H₈+3 HNO₃ C₇H₅N₃O₆+ 3 H₂O
1 mole of C₇H₈ reacts with 3 moles of nitric acid .454 g of C₇H₈ are converted to moles using molar mass and then it's related with moles of C₇H₈ and moles of nitric acid .Then, the moles of nitric acid are converted to grams
454 g C₇H₈×1 mole C₇H₈/92.14 g ×3 moles nitric acid/1 mole C₇H₈×63.01 g nitric acid/ 1 mole nitric acid=931 g
Thus, 931 g of nitric acid is required to react with 454 g C₇H₈.
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