Answer:
This is a simple case of ratios. (1 mol)/(22.4 L)=(n mol)/(.025 L) Then we cross multiply and we get 22.4n=.025 We divide each side by 22.4 to find n=.001116 mol Then to convert the moles to atoms we multiply, and cross-cancel the units (.001116 mol)/1 xx (6.02 xx 10^23 atms)/(1 mol) and we have 6.72 xx 10^20 atoms. I've found the trick of cross-cancelling units to be a very effective mnemonic, it always makes sure you carry out the correct calculation to find the desired units.
Explanation:
The Percent composition of MgO is 60.304 % and 39.696 % respectively.
<h3>
What percentage of the given chemical is there?</h3>
Mg + 1/2O₂ -------> MgO
We now want to know the percent composition of MgO in light of this reaction. Since the original reactants' and the product's mass are not provided, we can use the component's atomic weights to solve this problem.
Let's compute the molar mass of MgO since Mg has a molecular weight of 24.305 g/mol and O has a molecular weight of 15.999 g/mol:
molar mass of 
Now with this weight, let's see the percent composition of this compound:
Mg percentage =
%
O percentage =
%
The Percent composition of MgO is 60.304 % and 39.696 % respectively.
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Entropy Change is the measure of the randomness of the thermodynamic system. The entropy change for the reaction is -49.3 J/K.
<h3>What is the change in entropy?</h3>
Entropy change is the ratio of the heat transfer of the system to the absolute temperature of the system.
The entropy of nickel = 182.1 J/mol. K
The entropy of oxygen = 205.0 J/mol. K
The entropy of nickel oxide = 37.99 J/mol. K
Entropy change is calculated as:

Therefore, -49.3 J/K is the entropy change.
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Answer:
a base
Explanation:
first convert the pOH to pH, that way it will
be easy to decide.
formula:pOH+pH=14
pH=14-4.3=9.7
high pH tells us it's a base