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Leviafan [203]
1 year ago
7

What is the dependent variable in y=x+12

Mathematics
1 answer:
erma4kov [3.2K]1 year ago
8 0

The independent variable is x

y is dependent on the value of x

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Log(x)²=(logx)², find the value of x​
Gnesinka [82]

Answer:

x = 7.39

Step-by-step explanation:

log(x)²=(logx)², find the value of x​

log x² = log x * log x

2log x = log x * log x

2 = log x

Take the exponent pf both sides

e² = e^logx

e²  = x

x  = e²

x = 7.39

6 0
3 years ago
g A coffee-dispensing machine is supposed to deliver eight ounces of liquid into each paper cup, but a consumer believes that th
kap26 [50]

Answer: Reject the eight- ounces claim.

Step-by-step explanation:

For left tailed test , On a normal curve the rejection area lies on the left side of the critical value.

It means that if the observed z-value is less than the critical value then it will fall into the rejection region other wise not.

As per given ,

Objective : A coffee-dispensing machine is supposed to deliver eight ounces of liquid or less.

Then ,

H_0: \mu=8\\\\H_a: \mu , since alternative hypothesis is left-tailed thus the test is an left-tailed test.

the critical value for z for a one-tailed test with the tail in the left end is -1.645 and the obtained value is -1.87.

Clearly , -1.87 < -1.645

⇒ -1.87 falls under rejection region.

⇒  Decision : Reject null hypothesis.

i.e. we reject the eight- ounces claim.

6 0
4 years ago
Answer these for me please!
goldfiish [28.3K]

6 √5

7 π

Both continue on forever and will never have an exact answer - therefore, they're irrational.

3 0
3 years ago
Help please it due at 8
umka2103 [35]
I need help my self lol XD sorryyyyyyyyy88898
8 0
3 years ago
Five distinct numbers are randomly distributed to players numbers 1 through 5. Whenever two playerscompare their numbers, the on
ad-work [718]

Answer:

Observe that the first and the second player have equal probability to get any of number. Using the principle of that symmetry, we have that  

P(X=0)=\frac{1}{2}

<u>Event X = 1 </u>means that the first player has got greater number than the second player, but not than the third player. So, choose any three numbers out of five of them and say that the minimal number out of these three goes to the second player, mean number to the first one and the largest to the third one. Permute remaining two numbers on remaining two people. Hence

P(X=1)=\frac{1}{6}

<u>Event X = 2</u> means that the first player has got greater number than the second and the third player, but not than the fourth player. So, choose any four numbers out of five of them and say that the minimal number and the next minimal out of these four go to the second and the third player (and permute them), third number to the first one and the largest to the fourth player. Give remaining number to the last person. Hence

P(X=2)=\frac{1}{12}

<u>Event X = 3</u> means that the first player has got greater number than the second, the third, and the forth player, but not than the fifth player. So, permute these five numbers as follows: give the highest to the last person, the second highest to the first, and permute remaining numbers on the remaining people. Hence  

P(X=3)=\frac{1}{20}

<u>Event X = 4</u> means basically the first player has won all the battles i.e, he has got the greatest number. Hence

P(X=4)=\frac{1}{5}

7 0
3 years ago
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