Answer:
A)
Step-by-step explanation:
We know that the expression (x^2 - a^2) can be written as (x-a)(x+a). So an expression of this type: (x^2 - a^2) wouldn't be completely factored because it could be factorized even more.
So we know that 36 = 6^2, 49= 7^2 and 81 = 9^2. So if we choose any of these options (Option B, C and D) it wouldn't be completely factored.
The correct is the option A, given that if a=12, it wouldn't be a perfect square, so it would be completely factored.
Answer:
Step-by-step explanation:
![We\ are\ given:\\TU=SQ\\TP=PQ\\\angle TPU= \angle SPQ [Vertically\ Opposite\ Angles\ Are\ Equal]\\Hence,\\As\ we\ are\ given,\ 2\ sides\ and\ 1\ angle\ of\ each\ triangle\ correspond,\ we\\ could\ use\ the\ SAS\ Congruency Rule.\\But:\\](https://tex.z-dn.net/?f=We%5C%20are%5C%20given%3A%5C%5CTU%3DSQ%5C%5CTP%3DPQ%5C%5C%5Cangle%20TPU%3D%20%5Cangle%20SPQ%20%5BVertically%5C%20Opposite%5C%20Angles%5C%20Are%5C%20Equal%5D%5C%5CHence%2C%5C%5CAs%5C%20we%5C%20are%5C%20given%2C%5C%202%5C%20sides%5C%20and%5C%201%5C%20angle%5C%20of%5C%20each%5C%20triangle%5C%20correspond%2C%5C%20we%5C%5C%20could%5C%20use%5C%20the%5C%20SAS%5C%20Congruency%20Rule.%5C%5CBut%3A%5C%5C)
<em>As SAS Congruency Rule tells us that 'Two triangles are congruent only if two sides and an included angle of one triangle corresponds to two sides and an included angle of the other' .</em>
<em>Here,</em>
<em>As ∠TPU and ∠SPQ are NOT the included angle of ΔTUP and ΔSPQ respectively, the two triangles cannot be proven congruent through SAS Congruency.</em>
<em>Note: We also cannot apply SSA congruency as SSA congruency doesnt exist.</em>
Answer: 2
Step-by-step explanation:
Cost of Car= C
$19,028 <span>≥</span><span> C ≤ $370,790
</span>
The cost of the sports car is greater than or equal to $19, 028 and less than or equal to $370,790.
Answer:
-6
Step-by-step explanation:
You multiply -2 by 3 and you get -6.
2 negatives or 2 positives equals a positive number in Multiplication and Division.
But a Negative number and a positive number equals a negative number in Multiplication and Division.
