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Ivanshal [37]
1 year ago
7

How do I find the restrictions on x if there are any?

D%20%20%5Cfrac%7B5%7D%7Bx%20-%2010%7D%20" id="TexFormula1" title=" \frac{1}{x - 1} = \frac{5}{x - 10} " alt=" \frac{1}{x - 1} = \frac{5}{x - 10} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Natali5045456 [20]1 year ago
6 0

We have the expression:

\frac{1}{x - 1}=\frac{5}{x - 10}

When we have rational functions, where the denominator is a function of x, we have a restriction for the domain for any value of x that makes the denominator equal to 0.

That is because if the denominator is 0, then we have a function f(x) that is a division by zero and is undefined.

If we have a value that makes f(x) to be undefined, then this value of x does not belong to the domain of f(x).

Expression:

\begin{gathered} \frac{1}{x-1}=\frac{5}{x-10} \\ \frac{x-1}{1}=\frac{x-10}{5} \\ x-1=\frac{x}{5}-\frac{10}{5} \\ x-1=\frac{1}{5}x-2 \\ x-\frac{1}{5}x=-2+1 \\ \frac{4}{5}x=-1 \\ x=-1\cdot\frac{5}{4} \\ x=-\frac{5}{4} \end{gathered}

Answer: There is no restriction for x in the expression.

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Answer:

Amount of money Judy has in her account is \$(7500+n).

Amount of money Tommy has in his account is  \$(22506+3n)

Step-by-step explanation:

To find : Amount of money in Judy account and amount of money in Tommy account:

Solution:

Given:

Judy has $7500 more than a number in her account.

Let the number be 'n'.

So we can say that;

Amount of money in Judy account is equal to 7500 plus number.

framing in equation form we get;

Amount of money in Judy account = \$(7500+n)

Hence Amount of money Judy has in her account is \$(7500+n).

Now Given:

Tommy has 6 more than 3 times the amount of money in his bank account than Judy.

So we can say that;

Amount of money in Tommy account is equal to 3 multiplied by Amount of money in Judy account plus 6.

framing in equation form we get;

Amount of money in Tommy account = 3(7500+n)+6 =22500+3n+6=\$(22506+3n)

Hence Amount of money Tommy has in his account is  \$(22506+3n).

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Step-by-step explanation:

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