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ladessa [460]
3 years ago
13

Problem Set

Mathematics
1 answer:
guapka [62]3 years ago
4 0

Answer:idk

Step-by-step explanation:

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Assume that during each second, a job arrives at a webserver with probability 0.03. Use the Poisson distribution to estimate the
Savatey [412]

Answer:

The probability that at lest one job will be missed in 57 second is=1- e^{-1.71} =0.819134

Step-by-step explanation:

Poisson distribution:

A discrete random variable X having the enumerable set {0,1,2,....} as the spectrum, is said to be Poisson distribution.

P(X=x)=\frac{e^{-\lambda t}({-\lambda t})^x}{x!}  for x=0,1,2...

λ is the average per unit time

Given that, a job arrives at a web server with the probability 0.03.

Here λ=0.03, t=57 second.

The probability that at lest one job will be missed in 57 second is

=P(X≥1)

=1- P(X<1)

=1- P(X=0)

=1-\frac{e^{-1.71}(1.71)^0}{0!}

=1- e^{-1.71}

=0.819134

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