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Jlenok [28]
3 years ago
9

consider this expression 7+3.4+2 what movements does this represent for Cecil walking on his tightrope? draw a diagram to show h

is movements and length of his walk

Mathematics
1 answer:
Lina20 [59]3 years ago
5 0

Ok let me start it from here.

you are studying about properties of natural numbers or whole number or may be integers.

So , In this  Question you have to follow property of addition of integers.

⇒7+3=( You are at the point 7 on the number line or on the tight rope , you are moving (+3) on the right direction.) So you will reach at 7+1+1+1=10

⇒4+2=( You are at the point 4 on the number line or on the tight rope , you are moving (+2) on the right direction.) So you will reach at 4+1+1=6

In first case Cecil has taken total walk of 10 units and in second case Cecil has taken a walk of 10 units.

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nataly862011 [7]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Solve this polynomial expression please.
Sedbober [7]
-9x^3 +54x^2 -30x +12
5 0
3 years ago
Evaluate each logarithm. Do not use a calculator. Log (125)(1/25)
svetlana [45]

Answer:

-2/3

Step-by-step explanation:

Log125(1/25)=x

Raise each side to the base of 125

125^Log125(1/25)=125^x

1/25 = 125^x

Rewrite 25 as a power of 5  and 125 as a power of 5

1 / 5^2 = 5^3^x

The if power is in the denominator, we can bring it to the numerator by making it negative

5^-2 = 5^3^x

We know that a^b^c = a^(b*c)

5^-2 = 5^(3*x)

Since the bases are the same, the exponents are the same

-2 = 3x

Divide by 3

-2/3 = 3x/3

-2/3 =x

6 0
3 years ago
I need help with both questions...
NikAS [45]

Answer:

17. a)

Step-by-step explanation:

17.

f(x) =x/2, then f(x-3)=(x-3)/2

x=3, f(x-3)=f(3-3)=f(0)=0 (values in table)

f(x-3)+3=0+3=3

18.

f(x) =x/2

f(x-2) for x=5 is f(5-2)=f(3)=3/2

f(x-2)+5=f(3)+5=3/2+5=3/2+10/2=13/2

3 0
3 years ago
Read 2 more answers
If sin ⁡x=7/25, and 0 < x < π/2, what is cos⁡(x−3π/2)?
Likurg_2 [28]

Answer:

Cos(x-\frac{3\pi}{2})=-\frac{7}{25}

Step-by-step explanation:

Remember that cos(x-y)=cos(x)cos(y)+sin(x)sin(y)

Then,

cos(x-\frac{3\pi}{2})=cos(x)cos(\frac{3\pi}{2})+sin(x)sin(\frac{3\pi}{2})\\

But cos(\frac{3\pi}{2})=0 and sin(x)=\frac{7}{25}

Then

cos(x-\frac{3\pi}{2})=cos(x)*0+\frac{7}{25}*sin(\frac{3\pi}{2})\\=\frac{7}{25}*(-1)=\frac{-7}{25}

5 0
3 years ago
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