Answer:
103
Step-by-step explanation:
We are given two binomials: x+4 , x^2-9.
x+4 can't be factored. Therefore, it is a prime.
Let us work on x^2-9.
9 could be written as 3^2.
Therefore, x^2-9 = x^2 - 3^2.
Now, we can apply difference of the squares formula to factor it.
We know a^2 -b^2 = (a-b) (a+b).
Therefore, x^2 - 3^2 can be factored as (x-3) (x+3).
So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).
Answer:
w = (cv +dy) / (cb - ad)
Step-by-step explanation:
Multiply through by c
aw + y = c(bw + v) / d Multiply by d
d(aw + y) = c(bw + v) Remove the brackets
daw + dy = cbw + cv Subtract dy from both sides.
daw +dy - dy = cbw + cv -dy
daw = cbw + cv - dy Subtract cbw from both sides
daw - cbw = cbw - cbw + cv - dy
daw - cbw = cv - dy Isolate W on the left.
w(da - cb) = cv - dy Divide by cb - ad on both sides.
w = (cv - dy) / (ad - bc) Answer
Answer:
i'm not sure but i think its 7,14,21
Step-by-step explanation:
7,14,21
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