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Lerok [7]
3 years ago
11

Please help, showing work is not necessary but appreciated. Find the sum.

Mathematics
2 answers:
maks197457 [2]3 years ago
5 0
20+30+2=52
51+41+30=86
18+32+15=65

52+86+65=203  now I don't know what its sign would be but that is what it would equal all together without the signs 

hope that helps
marishachu [46]3 years ago
3 0
If I remember right, each column can only go up to 60. so add up to seconds, anything over 60 stays and 1 carries over to the minutes. add those up, anything over 60 stays, and 1 carries over to degrees. then add those.

I got 53° 27' 5"
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Anyone wanna attempt to help me
ArbitrLikvidat [17]

Answer:

t=57, u=31, v=92

Step-by-step explanation:

So we know that 180= 5x+2+2x+9+8x+4 which simplifies to 180 = 15x+15. Subtract 15 from both sides to get 165=15x and then divide by 15 to get 11=x. NOw we can plug this into the three angles as x so t = 5*11+2, t=55+2, t=57, then u = 2*11+9, u=22+9, u=31, and lastly v=8*11+4, v= 88+4, and v=92

7 0
2 years ago
Which of the following are necessary when proving that the opposite angles of a parallelogram are congruent? A. Opposite sides a
Misha Larkins [42]

Answer:

C and B

Step-by-step explanation:

The correct option is option B and C. The necessary condition to prove that the opposite angles of a parallelogram are congruent:

C. Angle Addition Postulate.

B. Opposite sides are congruent

8 0
3 years ago
Read 2 more answers
The average (arithmetic mean) of five different positive integers is 30. What is the greatest possible value of one of these int
geniusboy [140]

Answer:

The Greatest possible value of one of the integer is 140.

Step-by-step explanation:

Given:  The average (arithmetic mean) of five different positive integers is 30.

To find:  What is the greatest possible value of one of these integers?

Explanation: we are given that the arithmetic mean of five  positive integer

                   is 30.

Let the five positive integers are A,B,C,D,E

The arithmetic mean :

                   \frac{A+B+C+D+E}{5} =30.

On multiplying both side by 5.

                       A+B+C+D+E =150.

The least values of A ,B,C and D can be 1 ,2,3,4.

  Then :  1 +2+3+4+E =150

On simplification  10+E =150

On subtraction both side by 10 we get

                      E = 140 .

Therefore, the Greatest possible value of one of the integer is 140.


6 0
3 years ago
Rabekah is filling a cube-shaped box with small cubes. the volume of each of these cubes is 1 cubic centimeter. She has already
Vinvika [58]
Well it shows that the main cube is 9 blocks tall. It is a perfect cube, not a rectangular prism or anything, so every side is the same. So 9 cubed. Or, in other words, 9*9*9
8 0
3 years ago
1. 6(4x+1)=78<br>2. 2(x+10)=60<br><br>Solve for x​
postnew [5]

Answer:

1. x= -3

2. x= 20

Step-by-step explanation:

sorry if this is wrong,

7 0
2 years ago
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