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Salsk061 [2.6K]
3 years ago
8

Use the net to find the surface area of the cylinder

Mathematics
1 answer:
densk [106]3 years ago
7 0

Answer:

D) 120pi yd2

Step-by-step explanation:

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What is the answer to the problem i am very confused...
musickatia [10]
The time of takeoff of this hovercraft would be 0 seconds, as if you were starting a timer. So, if you plug in 0 for x (unit for seconds) in your equation, it will look like this:

h(0) = -3(0 - 3)² + 108
Parenthesis first
h(0) = -3(-3)² + 108
Exponents next
h(0) = -3(9) + 108
Multiplication
h(0) = -27 + 108
Combine like terms

h(0) = 81: The height of the hovercraft at the time of takeoff is 81 meters!
Hope this helps :)

7 0
3 years ago
Help please!! im stuck
Lady_Fox [76]

Answer:

<u>No</u>

Step-by-step explanation:

3/5 or 3 ÷ 5 = 0.60

6/7 or 6 ÷ 7 = about 0.8571

these two numbers/decimals are obviously not the same, making them inequivalent

7 0
2 years ago
Activity 5: COMPARE US! Write an inequality relating the given pair of angles or segment measures. Complete each statement by ch
Shalnov [3]

Answer:

1. LM < PN

2. AD < DC

3. m<CAB < m<CBA

4. m<1 = m<2

Step-by-step explanation:

Recall: an angle measure is relative to the length of the opposite side. That is, the longer the side opposite to an angle, the larger the measure of that angle and vice versa.

1. LM is opposite to <LNM,

PN is opposite to <NLP

m<LNM is less than m<NLP, therefore,

LM < PN

2. AD is opposite to <ABD

DC is opposite to <DBC

m<ABD is less than m<DBC, therefore,

AD < DC

3. m<CAB is opposite to CB

m<CBA is opposite to CA

CB is less than CA, therefore,

m<CAB < m<CBA

4. The side opposite to <1 is congruent to the side opposite to <2.

Therefore,

m<1 = m<2

3 0
2 years ago
=
Savatey [412]

Answer: 8 hours

Step-by-step explanation: First, find the unit rate. For one hour of work, she earns 0.05263157894. Multiply this number 152.

4 0
2 years ago
Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th
mihalych1998 [28]

Question:

1. The females worked less than the males, and the female median is close to Q1.

2. There is a high data value that causes the data set to be asymmetrical for the males.

3. There are significant outliers at the high ends of both the males and the females.

4. Both graphs have the required quartiles.

Answer:

The correct option is;

1. The females worked less than  the males, and the female median is close to Q1

Step-by-step explanation:

Based on the given data, we have;

For males

Minimum = 0

Q1 = 1

Median or Q2 = 20

Q3 = 25

Maximum = 50

For females;

Minimum = 0

Q1 = 5

Median or Q2 = 6

Q3 = 10

Maximum = 18

Therefore, the values of data that affect the statistical measures of spread and center are that

The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range

Also the female median is very close to Q1, therefore it affects the definition of a measure of center.

5 0
3 years ago
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