The width of the square is 7 cm. This is also the diameter of the circle.
To find the area of the square, you do 7², which is 49 cm².
To find the area of a circle, you do πr².
The radius is half the diameter, so it's 7 ÷ 2, which is 3.5 cm.
π3.5² ≈ 38.4845100065 cm².
The shaded region is the area of the square minus the area of the circle.
49 - 38.4845100065 = <span>10.5154899935, but because you're using 3.14 to approximate pi, the closest answer is 10.54 cm</span>².
The answer is 10.54 cm².
Answer:
40%
Step-by-step explanation:
To find the percentage in each game, you divide the number of successful shots by the number of total shots. For game 1, this looks like: 8/22 = 0.3636, or 36%.
For game 2, this give us 40%, and for game 3, 43%.
Not sure if the question is asking for a game-by-game answer or a grand total, so we'll do both. To find the total percentage over the course of the games, add all the successful shots (8 + 6 + 10 = 24) and all the attempted shots (22 + 15 + 23 = 60), and divide the same way (24 / 60 = 40%).
Answer:
$1.88
Step-by-step explanation:
Answers:
(a) p + m = 5
0.8m = 2
(b) 2.5 lb peanuts and 2.5 lb mixture
Explanations:
(a) Note that we just need to mix the following to get the desired mixture:
- peanut (p) - peanuts whose amount is p
- mixture (m) - mixture (80% almonds and 20% peanuts) that has an amount of m; we denote this as
By mixing the peanuts (p) and the mixture (m), we combine their weights and equate it 5 since the mixture has a total of 5 lb.
Hence,
p + m = 5
Note that the desired 5-lb mixture has 40% almonds. Thus, the amount of almonds in the desired mixture is 2 lb (40% of 5 lb, which is 0.4 multiplied by 5).
Moreover, since the mixture (m) has 80% almonds, the weight of almonds that mixture is 0.8m.
Since we mix mixture (m) with the pure peanut to get the desired mixture, the almonds in the desired mixture are also the almonds in the mixture (m).
So, we can equate the amount of almonds in mixture (m) to the amount of almonds in the desired measure.
In terms mathematical equation,
0.8m = 2
Hence, the system of equations that models the situation is
p + m = 5
0.8m = 2
(b) To solve the system obtained in (a), we first label the equations for easy reference,
(1) p + m = 5
(2) 0.8m = 2
Note that using equation (2), we can solve the value of m by dividing both sides of (2) by 0.8. By doing this, we have
m = 2.5
Then, we substitute the value of m to equation (1) to solve for p:
p + m = 5
p + 2.5 = 5 (3)
To solve for p, we subtract both sides of equation (3) by 2.5. Thus,
p = 2.5
Hence,
m = 2.5, p = 2.5
Therefore, the solution to the system is 2.5 lb peanuts and 2.5 lb mixture.
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